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Javascript 从跨域sencha读取JSON数组_Javascript_Extjs_Sencha Touch - Fatal编程技术网

Javascript 从跨域sencha读取JSON数组

Javascript 从跨域sencha读取JSON数组,javascript,extjs,sencha-touch,Javascript,Extjs,Sencha Touch,我想存储来自另一个域的json对象数组。我已经在代理中尝试了所有可能的配置,但仍然不起作用。所以请帮帮我 响应数组: [ { "id": 1, "title": "Take A Bow", "artist": "Rihanna", "cover": "resources/images/cd-covers/take-a-bow.jpeg", "audio": "http://home.no/hamed2ganja12/Single/Rihanna%20-%2

我想存储来自另一个域的json对象数组。我已经在代理中尝试了所有可能的配置,但仍然不起作用。所以请帮帮我

响应数组:

[
{
    "id": 1,
    "title": "Take A Bow",
    "artist": "Rihanna",
    "cover": "resources/images/cd-covers/take-a-bow.jpeg",
    "audio": "http://home.no/hamed2ganja12/Single/Rihanna%20-%20Take%20A%20Bow%20%28www.Iran2Music.Org%29.mp3"
},
{
    "id": 2,
    "title": "Ridin' Solo",
    "artist": "Jason Derulo",
    "cover": "resources/images/cd-covers/ridin-solo.jpeg",
    "audio": "http://ms11.cyworld.com.cn/d044/2010/05/01/167/1272686567306986_file.mp3"
},
{
    "id": 3,
    "title": "Hero",
    "artist": "Nickelback",
    "cover": "resources/images/cd-covers/hero.jpeg",
    "audio": "http://api.ning.com/files/hXzO1QWnGr6ZgtB05IbaLW5IId7mjLPvOMGA0I8JHY*u*ZMCrczyw*XZrimUE7XQHFHgOLWa2b8s0xGfoHg5nRs-J84KlSGO/NickelBackHeroSpidermanTheme.mp3"
}]
型号:

Ext.define('MyApp.model.Track', {
extend: 'Ext.data.Model',
config: {
    fields: [
        { name: 'id',     type: 'int'    },
        { name: 'title',  type: 'string' },
        { name: 'artist', type: 'string' },
        { name: 'cover',  type: 'string' },
        { name: 'audio',  type: 'string' }
    ]
}   
});
商店:

Ext.create('Ext.data.Store',{
requires:['MyApp.model.Track'],
autoLoad:true,
model:'MyApp.model.Track',
storeId:'myStore',
autoSync:true,
fields:["title","artist"],
proxy:{
type:'jsonp',
url: 'http://www.tux-components.com/examples/playlist/app/music.json',
reader: {
            type: 'json'
            }    
 },
listeners:{
load: function(store, records, successful,operation,eOpts){
console.log('loaded records count is '+store.getCount());
}
}

});
我发现它给出了超时错误。但URL在浏览器中运行良好。
接下来我该怎么办?请帮助我。

远程服务器返回的数据需要是JSONP,而不是JSON-主要区别在于包装返回对象的回调函数

我不知道您使用的是什么框架/版本,但请仔细阅读API文档-所有答案都在其中