Javascript 验证数据并发布到mysql数据库的简单表单

我想要一个员工输入订单ID的简单表单。该ID将通过第二次输入进行验证。验证后，它将通过服务器上的insert.php传递到数据库

以下是我到目前为止所写的内容。如何在成功检查时推送数据，或在失败时清除表单，这让我感到困惑

<script type="text/javascript" language="JavaScript">
<!--
//--------------------------------
// This code compares two fields in a form and submit it
// if they're the same, or not if they're different.
//--------------------------------
function checkid(theForm) {
    if (theForm.orderid1.value != theForm.orderid2.value)
    {
        alert('The two values don\'t match! Please check!');
        return false;
    } else {
        return true;
    }
}
//-->
</script> 




<form action="../" onsubmit="return checkid(this);">
<form action="insert.php" method="post">

<p> Enter the compleated Order ID<br>
<input type="TEXT" name="orderid1" size="20" maxlength="20"> 
<br>
Please Confirm the order ID!
<br>
<input type="TEXT" name="orderid2" size="20" maxlength="20"> 
<br>
<input type="SUBMIT" value="Compleate Order!"></p> 
</form>

---

无论如何，这是你的答案

<script type="text/javascript" language="JavaScript">
<!--
//--------------------------------
// This code compares two fields in a form and submit it
// if they're the same, or not if they're different.
//--------------------------------
function checkid(theForm) {
    if (theForm.orderid1.value != theForm.orderid2.value)
    {
        alert('The two values don\'t match! Please check!');
        return false;
    } else {
        return true;
    }
}
//-->
</script> 




<form action="insert.php" onsubmit="return checkid(this);" method="post">

<p> Enter the compleated Order ID<br>
<input type="TEXT" name="orderid1" size="20" maxlength="20"> 
<br>
Please Confirm the order ID!
<br>
<input type="TEXT" name="orderid2" size="20" maxlength="20"> 
<br>
<input type="SUBMIT" value="Compleate Order!"></p> 
</form>

---

查看下面的问答，了解使用JavaScript发布的示例：为什么有2个？表单操作=../onsubmit=返回checkidthis；>这是什么？