Javascript 如何在一页中使用多页向下?
我尝试了下面的代码,但它只在第一个Javascript 如何在一页中使用多页向下?,javascript,jquery,pagedown,Javascript,Jquery,Pagedown,我尝试了下面的代码,但它只在第一个.wmd输入中添加了pagedown按钮 if ($(".wmd-input").length > 0) { var converter = new Markdown.Converter(); var help = function () { alert("Do you need help?"); } var options = { helpButton: { handler: help }, str
.wmd输入中添加了pagedown按钮
if ($(".wmd-input").length > 0) {
var converter = new Markdown.Converter();
var help = function () { alert("Do you need help?"); }
var options = {
helpButton: { handler: help },
strings: {quoteexample: "whatever you're quoting, put it right here"}
};
var editors = [];
var i = 0;
$(".wmd-input").each(function() {
editors[i] = new Markdown.Editor(converter, "", options);
editors[i].run();
i = i + 1;
});
}
看起来我必须为wmd的每个元素添加唯一的ID。我的意思是wmd输入
,wmd预览
和wmd按钮栏
。我以编程方式修改了这个id属性。这可以通过手动修改来完成,但我的输入长度是动态的
// make wmd's id's unique
var pBox = $(this).parents(".box");
$(pBox).find("textarea").attr('id', "wmd-input" + i);
$(pBox).children("#wmd-preview").attr('id', "wmd-preview" + i);
$(pBox).find("#wmd-button-bar").attr('id', "wmd-button-bar" + i);
所以当这个ID属性被设置时,我用postfix变量调用编辑器,问题就解决了
editors[i] = new Markdown.Editor(converters[i], i, options);
你应该自己把答案作为答案,然后接受它(而不是编辑问题)。见:
if ($(".wmd-input").length > 0) {
var converters = [];
var editors = [];
var i = 1;
$(".wmd-input").each(function() {
converters[i] = new Markdown.Converter();
var help = function () { alert("Do you need help?"); }
var options = {
helpButton: { handler: help },
strings: {quoteexample: "whatever you're quoting, put it right here"}
};
// make wmd's id's unique
var pBox = $(this).parents(".box");
$(pBox).find("textarea").attr('id', "wmd-input" + i);
$(pBox).children("#wmd-preview").attr('id', "wmd-preview" + i);
$(pBox).find("#wmd-button-bar").attr('id', "wmd-button-bar" + i);
editors[i] = new Markdown.Editor(converters[i], i, options);
editors[i].run();
i = i + 1;
});
}