Javascript 基于现有数据更新Alasql数据库详细信息

Javascript 基于现有数据更新Alasql数据库详细信息,javascript,mysql,angularjs,node.js,alasql,Javascript,Mysql,Angularjs,Node.js,Alasql,我有一个如下所示的Alasql数据库: results Name Recieved Bill 10/11/17 7:42 AM Susan 10/05/17 3:43 AM Sarah 10/04/17 2:08 PM alasql.fn.toTimestamp = function(date) { return new Date(date).getTime() / 1000; } alasql(`UPDATE result SET Received =

我有一个如下所示的Alasql数据库:

results
Name      Recieved
Bill      10/11/17 7:42 AM
Susan     10/05/17 3:43 AM
Sarah     10/04/17 2:08 PM
alasql.fn.toTimestamp = function(date) {
  return new Date(date).getTime() / 1000;
}
alasql(`UPDATE result SET Received = toTimestamp(Received)`);
我正在尝试更新它,以转换接收的
表,并将其转换为unix时间戳

这就是我所尝试的:

alasql(`UPDATE result SET Recieved = ${new Date(Recieved).getTime()}`);
我在节点中遇到此错误:

ReferenceError:未定义Received


如何使用从数据库接收的现有
数据并对其执行变异?

如果有人遇到此问题,alasql允许使用如下自定义函数:

results
Name      Recieved
Bill      10/11/17 7:42 AM
Susan     10/05/17 3:43 AM
Sarah     10/04/17 2:08 PM
alasql.fn.toTimestamp = function(date) {
  return new Date(date).getTime() / 1000;
}
alasql(`UPDATE result SET Received = toTimestamp(Received)`);