Javascript 收到事件时加载另一个.html页面

Javascript 收到事件时加载另一个.html页面,javascript,android,jquery,html,touchswipe,Javascript,Android,Jquery,Html,Touchswipe,我正在使用一个html/javascript混合android应用程序。基本上,我想启用触摸/滑动,以便用户可以向左/向右滑动以转到下一页/上一页 <div id="test" class="box">Index</div> <script> $(function() { //Enable swiping... $("#test").swipe( {

我正在使用一个html/javascript混合android应用程序。基本上,我想启用触摸/滑动,以便用户可以向左/向右滑动以转到下一页/上一页

<div id="test" class="box">Index</div>
    <script>
        $(function() {          
            //Enable swiping...
            $("#test").swipe( {
                swipe:function(event, direction) {
                    //direction returns four events: left, right, up & down
                    //depending on which direction you swiped on the page
                },
              //Default is 75px, set to 0 for demo so any distance triggers swipe
               threshold:75
            });
        });
    </script>
否则,如果事件是“正确的”,我想

window.location.href = "about.html";
window.location.href = "home.html";
更新:找到了答案,答案很简单。我把自己弄得太复杂了

if(direction=='left'){
        window.location.href = "GuidedTour.xhtml";
      }else if(direction=='right'){
        window.location.href = "../index.html";
      }
if(direction=='left'){
    window.location.href = "GuidedTour.xhtml";
  }else if(direction=='right'){
    window.location.href = "../index.html";
  }

尝试使用jquery来实现以下效果:

$("#test").swipe(function(event){
    window.open($("http://putyourlinkhere.com").attr('href'),'_blank');
},'left');

更新:弄明白了,答案很简单。我把自己弄得太复杂了

if(direction=='left'){
        window.location.href = "GuidedTour.xhtml";
      }else if(direction=='right'){
        window.location.href = "../index.html";
      }
if(direction=='left'){
    window.location.href = "GuidedTour.xhtml";
  }else if(direction=='right'){
    window.location.href = "../index.html";
  }