Javascript 数组计数中的唯一值

我有一个如下所示的数组

var data = [
            ["1"," 101_30.1.101_34","0.0200112629","mm/s","[OK]"],
            ["1"," 101_30.1.101_35","0.0146548533","mm/s","[OK]"],
            ["1"," 101_30.1.101_45","0.0146548533","mm/s","[OK]"],
            ["1"," 101_42.2.101_43","0.0101406257","mm/s","[OK]"],
            ["2"," 102_17.3.102_38","5.1719756","mm/s","[WA]"],
            ["2"," 102_17.3.102_39","3.5886707","mm/s","[WA]"],
            ["2"," 102_17.3.102_44","9.4615074E-4","mm/s","[OK]"],
            ["2"," 102_40.4.102_41","4.8159785","mm/s","[OK]"],
            ["3"," 204_15","3.8374166","mA","[OK]"],
            ["4"," 501_11","1027.5156","RPM","[WA]"]
           ]

我想做的是找出有多少个唯一的数组。例1=4,2=4,3=1,4=1

数据来自数据库，因此数组的数量总是可以更改的

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下面是我所说的简单内容

试试这样的方法：

var count = {};
$.each(data, function(){
    var num = this[0]; // Get number
    count[num] = count[num]+1 || 1; // Increment counter for each value
});
console.log(count); // {1: 4, 2: 4, 3: 1, 4: 1}

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试着这样做：

var count = {};
$.each(data, function(){
    var num = this[0]; // Get number
    count[num] = count[num]+1 || 1; // Increment counter for each value
});
console.log(count); // {1: 4, 2: 4, 3: 1, 4: 1}

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你是在寻找数组第一个值的副本吗？…你的问题是？只需在数组中迭代并计算每个元素的第一个元素的出现次数。是的，基本上我是在寻找第一个值的副本。我不想删除它们，我只需要对它们进行计数。你是在寻找数组第一个值的重复项吗？…你的问题是？只需在数组中迭代并计算每个元素的第一个元素的出现次数。是的，基本上我在寻找第一个值的重复项。“我不想移除它们，我只需要数一数。”RocketHazmat我试过这个，但出于某种原因，它只能数到9？例：{1:84，2:97，3:31，4:57，5:28，6:21，7:28，8:25，9:18}还有，我可以添加什么来删除重复的内容呢？@Patrick:这个问题已经有三年了。为什么不问一个新的呢？如果你不想，至少告诉我你想做什么。“你说只数到9是什么意思？”RocketHazmat我试过这个，但出于某种原因，它只数到9？例：{1:84，2:97，3:31，4:57，5:28，6:21，7:28，8:25，9:18}还有，我可以添加什么来删除重复的内容呢？@Patrick:这个问题已经有三年了。为什么不问一个新的呢？如果你不想，至少告诉我你想做什么。你只数到9点是什么意思？