Javascript 不带特定单词的行匹配正则表达式

我试图创建一个正则表达式，它只计算行首不包含特定单词的行。在我的例子中，“迪蒙：”

但这场比赛的其余部分都落在了“迪蒙：”后面，这也是我不想要的

输入：

deamon: parsing arguments...
deamon: parsing xml file...
deamon: creating xml file for demo...
deamon: executing demo
parsing arguments...
path to xml: /home/www/www/seg-chapter/tests/users/1/launches/60/demo.xml
parsing xml file...

parsing arguments...
parsing xml file...
creating xml file for demo...
executing demo
parsing arguments...
path to xml: /home/www/www/seg-chapter/tests/users/1/launches/60/demo.xml
parsing xml file...

parsing arguments...
path to xml: /home/www/www/seg-chapter/tests/users/1/launches/60/demo.xml
parsing xml file...

匹配：

deamon: parsing arguments...
deamon: parsing xml file...
deamon: creating xml file for demo...
deamon: executing demo
parsing arguments...
path to xml: /home/www/www/seg-chapter/tests/users/1/launches/60/demo.xml
parsing xml file...

parsing arguments...
parsing xml file...
creating xml file for demo...
executing demo
parsing arguments...
path to xml: /home/www/www/seg-chapter/tests/users/1/launches/60/demo.xml
parsing xml file...

parsing arguments...
path to xml: /home/www/www/seg-chapter/tests/users/1/launches/60/demo.xml
parsing xml file...

我只想要：

deamon: parsing arguments...
deamon: parsing xml file...
deamon: creating xml file for demo...
deamon: executing demo
parsing arguments...
path to xml: /home/www/www/seg-chapter/tests/users/1/launches/60/demo.xml
parsing xml file...

parsing arguments...
parsing xml file...
creating xml file for demo...
executing demo
parsing arguments...
path to xml: /home/www/www/seg-chapter/tests/users/1/launches/60/demo.xml
parsing xml file...

parsing arguments...
path to xml: /home/www/www/seg-chapter/tests/users/1/launches/60/demo.xml
parsing xml file...

你知道如何只匹配行首没有“deamon:”的行吗

str.match( /^(?!deamon:).*/mg )

多行标志

m

表示

^

匹配每行的开头，而不仅仅是字符串的开头。

（？！deamon:）

是一种消极的前瞻，如果一行以

deamon:

开头，它会阻止匹配