Javascript 基于其他数据结构更新angularJS中的数据结构

我刚进入angularJS，在我的第一个项目中，我试图构建一个测验创建者。我希望人们能够创建结果、问题、答案以及答案到结果的加权映射。我的html如下所示：

<div ng-controller="QuizCtrl">

<div class="result" ng-repeat="result in quiz.results">
    <input ng-model="result.title" /> [<a href ng-click="quiz.results.splice($index, 1)">X</a>]<br />
</div>

<div class="question row" ng-repeat="question in quiz.questions">
  <div class="col-sm-4 col-md-4 col-lg-4">
  <input ng-model="question.title" /> [<a href ng-click="quiz.questions.splice($index, 1)">X</a>]<br />
    <a href ng-click="addAnswer($index)">add answer</a>
  </div>
  <div class="col-sm-8 col-md-8 col-lg-8">
    <div class="answer" ng-repeat="answer in question.answers">
      <input ng-model="answer.title" /> [<a href ng-click="question.answers.splice($index, 1)">X</a>]<br />
      <div class="answerresult" ng-repeat="answerresult in answer.answerresults">
        {{ quiz.results[$index].title }}:
        <select ng-change="answerresult.result = $index" ng-model="answerresult.weight" ng-options="i for i in [1,2,3]"></select>
      </div>
    </div>
  </div>
</div>

</div>

angular.module('testApp')
  .controller('QuizCtrl', function ($scope) {
    $scope.quiz = {
        questions: [
            {title: 'question 1', answers: [
                {title: 'answer 1', answerresults:[
                    {'result': 0, weight: 2},
                    {'result': 1, weight: 3}
                ]},
                {title: 'answer 3', answerresults:[
                    {'result': 0, weight: 2},
                    {'result': 1, weight: 2}
                ]}
            ]},
            {title: 'question 2', answers: [
                {title: 'answer 1', answerresults:[
                    {'result': 0, weight: 1},
                    {'result': 1, weight: 2}
                ]},
                {title: 'answer 2', answerresults:[
                    {'result': 0, weight: 2},
                    {'result': 1, weight: 2}
                ]},
                {title: 'answer 3', answerresults:[
                    {'result': 0, weight: 1},
                    {'result': 1, weight: 3}
                ]}
            ]}
        ],
        results: [
          {title: 'result 1'},
          {title: 'result 2'}
        ],
    };
});

现在我的问题是：

每当我向“$scope.quick.results”添加或删除新项目时，如何更新每个“$scope.quick.questions[x].answerresults”数组？当然，嵌套for循环也可以，但这并不十分优雅。。有没有更好的方法使用角度双向数据绑定

如何表示“$scope.quick.questions[x].答案[y].回答结果[z].结果”和“$scope.quick.results[I]”之间的关系？现在我刚刚设置了这个：ng change=“answerresult.result=$index”常规做法？还是有更好的办法

与其迭代“$scope.quick.questions[x].答案[y].answerresults”，不如迭代“$scope.quick.results”，然后为每个答案动态创建answerresults数组

---

提前感谢您的回答，如果这是一个愚蠢的问题，请道歉。我昨天刚跳进angular…

好的，我现在用嵌套for循环解决了这个问题。我不知道这在angular中是否是正确的方法，但它是有效的：

$scope.addResult = function() {
  $scope.quiz.results.push({});

  for(var question in $scope.quiz.questions ) {
    for(var answer in $scope.quiz.questions[question].answers) {
        $scope.quiz.questions[question].answers[answer].answerresults.push({});
    }
  }
};

$scope.removeResult = function(index) {
  $scope.quiz.results.splice(index, 1);

  for(var question in $scope.quiz.questions ) {
    for(var answer in $scope.quiz.questions[question].answers) {
        $scope.quiz.questions[question].answers[answer].answerresults.splice(index, 1);
    }
  }
};