Javascript AngularJS-如何重构我的茉莉花规格？

我使用AngularJS 1.2.16和Jasmine 2.X作为我的javascript规范。
但他们很快就变得一团糟。我很难找到关于如何重构和构建规范的信息

以下是我的一些不好的规格：

  channel = mockRestangular = $httpBackend = deferred = undefined
  channel_id = {...}

  beforeEach ->
    module("channels", ($provide) ->
      mockRestangular = {
        configuration: { baseUrl: "" }
        one: ->
          this
        post: ->
          this
        put: ->
          this
        ...
      }

      module ($provide) ->
      $provide.value('Restangular', mockRestangular)
      return
    )

  beforeEach inject((_channel_, $q, $injector) ->
    channel = _channel_
    $httpBackend = $injector.get('$httpBackend')
    deferred = $q.defer()
  )

    it "spec1", inject(($q, $rootScope) ->
      deferred = $q.defer()
      spyOn(mockRestangular.one().one(), 'get').and.returnValue(deferred.promise)
      spyOn(channel::, 'init').and.stub()
      new_channel = new channel(channel_id)
      new_channel.updateCount()
      deferred.resolve({"channels":[{...long...long...object...}]})
      $rootScope.$digest()
      expect(new_channel.meta.totalProducts).toEqual(24849)
      expect(new_channel.meta.activeProducts).toEqual(1349)
    )

    it "spec2", inject(($q, $rootScope) ->
      deferred = $q.defer()
      spyOn(mockRestangular.one().one(), 'get').and.returnValue(deferred.promise)
      spyOn(channel::, 'init').and.stub()
      new_channel = new channel(channel_id)
      new_channel.updateStatisticsRevenue()
      deferred.resolve({"revenue_statistics":[{...another...very...very...long...object...}]})
      $rootScope.$digest()
      expect(new_channel.statistics.revenue).toEqual([{...kinda...long...object...result...}])
    )

  # spec with real respond-mock objects
  describe "describtor2", ->
    it "spec3", inject(($rootScope) ->
     $httpBackend.expectPUT().respond(201,
  {products:[{"sku":"10413161","active":false,"min_price":{"fractional":400,"currency":"EUR"},"max_price":{"fractional":950,"currency":"EUR"}},{"sku":"10413162","active":true,"min_price":{"fractional":458,"currency":"EUR"},"max_price":{"fractional":799,"currency":"EUR"}}]})
     spyOn(mockRestangular.one().one(), 'get').and.returnValue(deferred.promise)
     spyOn(channel::, 'init').and.stub()
     new_channel = new channel channel_id
     new_channel.updateProducts()
     new_channel.getMeta().activeProducts = 2
     expect(mockRestangular.one().one().get).toHaveBeenCalled
     deferred.resolve({"products":[{"sku":"10413161","active":true,"min_price":{"fractional":412,"currency":"EUR"},"max_price":{"fractional":890,"currency":"EUR"}},{"sku":"10413162","active":true,"min_price":{"fractional":448,"currency":"EUR"},"max_price":{"fractional":799,"currency":"EUR"}}]}
     )
     $rootScope.$digest()
     new_channel.updateProduct([{sku:"10413161",active:false,min_price:{fractional:400,currency:"EUR"},max_price:{fractional:950,currency:"EUR"}},{"sku":"10413162","active":true,"min_price":{"fractional":458,"currency":"EUR"},"max_price":{"fractional":799,"currency":"EUR"}}])
     $httpBackend.flush()
     expect(new_channel.getProducts()).toEqual(
[{"sku":"10413161","active":false,"min_price":{"fractional":400,"currency":"EUR"},"max_price":{"fractional":950,"currency":"EUR"}},{"sku":"10413162","active":true,"min_price":{"fractional":458,"currency":"EUR"},"max_price":{"fractional":799,"currency":"EUR"}}]
     )
     expect(new_channel.getMeta().activeProducts).toBe(1)
)

因为它们很长，里面有所有的对象，我甚至开始在一个规范中加入更多的“期望值”。我知道这是错误的，但我害怕那些巨大的规范

---

Jasmine规范的结构化或重构有什么最佳实践吗？

在每个规范之前使用

来放置每个规范的一些初始通用代码，例如，您可以放置以下行：

      deferred = $q.defer()
      spyOn(mockRestangular.one().one(), 'get').and.returnValue(deferred.promise)
      spyOn(channel::, 'init').and.stub()
      new_channel = new channel(channel_id)

在每个

之前的

中，关联到相关的
描述

beforeEach(function() {
      deferred = $q.defer();
      spyOn(mockRestangular.one().one(), 'get').and.returnValue(deferred.promise);
      spyOn(channel::, 'init').and.stub();
      new_channel = new channel(channel_id);
});

其他选择：创建一些基本javascript函数来收集公共代码。
这样做的好处是，您可以命名代码的以下部分：

function mockDBGet() {
          deferred = $q.defer();
          spyOn(mockRestangular.one().one(), 'get').and.returnValue(deferred.promise);
}

function initChannel() {
          spyOn(channel::, 'init').and.stub();
          new_channel = new channel(channel_id);
}
//.......
it('myCurrentSpec', function(){
  mockDBGet();
  initChannel();   far more clean than your previous version
});

每次之前的
都很好。对于每个不知道的人，就像我一样，每个描述都可以在每个函数之前有自己的
。另一种选择听起来很有趣，你能给出一些例子/进一步的链接吗？更新为example.Ohh-ja。真漂亮。对于如何处理更大的模拟响应对象，您有什么想法吗？我想如果我们可以加上这一点，你提供了一个a+的答案，关于我和其他可能的问题。这个想法是出现一个等级的规格。看看这个：（Java示例，但与Jasmine非常相似）具有特定设置的“上下文”层次结构支持设置的分解。（
beforeach
在茉莉花语中）。=>请毫不犹豫地声明对应于特定上下文的嵌套
descripe
，这样您就可以从父级上下文的初始化（mock等）中获益。感谢链接。我只是想知道是否有一个很好的解决方案来存储更大的（200多个字符的模拟响应）。将它们存储在自己的函数上下文中甚至可能还不够。只是分离规格和模拟。有没有最佳实践？