Javascript 测试Jasmine中的空对象失败
如果将变量设置为Javascript 测试Jasmine中的空对象失败,javascript,angularjs,jasmine,karma-jasmine,Javascript,Angularjs,Jasmine,Karma Jasmine,如果将变量设置为{},则会出现以下匹配错误 // Somewhere in my angular controller self = this; self.myVar = {}; // In my test file // This errors out. I console.log myVar to make sure that it is indeed {} expect(myVar).toEqual({}); // Note if I define myVar = {} in the
{}
,则会出现以下匹配错误
// Somewhere in my angular controller
self = this;
self.myVar = {};
// In my test file
// This errors out. I console.log myVar to make sure that it is indeed {}
expect(myVar).toEqual({});
// Note if I define myVar = {} in the same test spec it works
it('test', function(){
var myVar = {};
expect(myCtrl.myVar).toEqual({});
expect({}).toEqual({});
});
这是什么原因?你会如何通过这种行为?根据Jasmine博士的说法
it("should work for objects", function() {
var foo = {
a: 12,
b: 34
};
var bar = {
a: 12,
b: 34
};
expect(foo).toEqual(bar);
似乎toEqual应该测试对象内容?我认为您的变量超出了应用程序的范围,在测试用例中,它将作为未定义的变量执行尝试:
expect(result).toMatchObject({})
您可以尝试使用与要计算的对象中存在的对象键关联的length属性:
expect(Object.keys(res).length).toBe(0); // or not.toBeGreaterThan(0)
如果要评估非空对象,可以使用:
expect((Object.keys(res)).length).toBeGreaterThan(0) // or not.toBe(0)
var empty=jasmine.empty();
expect(empty.asymmetricMatch(myvar));
=>/请张贴控制器。除非
myVar
是一个全局变量(这是不好的)expect(myVar).toEqual({})代码>无效