Javascript node.js在res.writeHeads（）函数中使用一个变量

你好。我有以下问题：

我用这个

res.writeHead(200, {
    "Content-Length": template["stylecss"].length,
    "Connection": "Close",
    "X-XSS-Protection": "1; mode=block",
    "Server": servername,
    "Content-Type": "text/css"
});

将响应头写入客户端

但是现在，我想更改上面的代码以提供预定义的头。大概是这样的：

var defresheads={“X-Frame-Options”：“deny”，“X-Powered-By”：servername}

res.writeHead(200, {
    defresheads,
    "Content-Length": template["stylecss"].length,
    "Connection": "Close",
    "X-XSS-Protection": "1; mode=block",
    "Server": servername,
    "Content-Type": "text/css"
});

现在，当我运行脚本时，它显示以下内容：

/home/dontrm/dontrm.js:47
            defresheads,
                       ^
SyntaxError: Unexpected token ,

---

还有其他方法吗？

使用helper函数连接头对象，如

function jsonConcat(o1, o2) {
    for (var key in o2) {
        o1[key] = o2[key];
    }
    return o1;
}

然后您可以按如下方式使用它：

var defresheads = { "X-Frame-Options": "deny", "X-Powered-By": servername };
res.writeHead(200, jsonConcat(defresheads, {
    "Content-Length": template["stylecss"].length,
    "Connection": "Close",
    "X-XSS-Protection": "1; mode=block",
    "Server": servername,
    "Content-Type": "text/css"
}));

---

使用一个helper函数连接头对象，如

function jsonConcat(o1, o2) {
    for (var key in o2) {
        o1[key] = o2[key];
    }
    return o1;
}

然后您可以按如下方式使用它：

var defresheads = { "X-Frame-Options": "deny", "X-Powered-By": servername };
res.writeHead(200, jsonConcat(defresheads, {
    "Content-Length": template["stylecss"].length,
    "Connection": "Close",
    "X-XSS-Protection": "1; mode=block",
    "Server": servername,
    "Content-Type": "text/css"
}));