Javascript 在对象数组中循环以提取特定数据

我正在构建一个node express angular twitter状态分析器，并试图找出如何从中提取tex并将其分配给一个长字符串以供以后使用

我正在尝试提取如下用户状态：

   client.get('statuses/user_timeline', {params, count:20}, function(error, tweets, response) {
    var jsonObject;
    if (!error) {
      analyze.analyze(tweets);
      }
  });

响应如下所示：

    [
  {
    "coordinates": null,
    "favorited": false,
    "truncated": false,
    "created_at": "Wed Aug 29 17:12:58 +0000 2012",
    "id_str": "240859602684612608",
    "entities": {
      "urls": [
        {
          "expanded_url": "/blog/twitter-certified-products",
          "url": "",
          "indices": [
            52,
            73
          ],
          "display_url": "
        }
      ],
      "hashtags": [

      ],
      "user_mentions": [

      ]
    },
    "in_reply_to_user_id_str": null,
    "contributors": null,
    "text": "Introducing the Twitter Certified Products Program: ",
    "retweet_count": 121,
    "in_reply_to_status_id_str": null,
    "id": 240859602684612608,
    "geo": null,
    "retweeted": false,
    "possibly_sensitive": false,
    "in_reply_to_user_id": null,
    "place": null,
    "user": {
      "profile_sidebar_fill_color": "DDEEF6",
      "profile_sidebar_border_color": "C0DEED",
      "profile_background_tile": false,
      "name": "Twitter API",
      "profile_image_url": ",
      "created_at": "Wed May 23 06:01:13 +0000 2007",
      "location": "San Francisco, CA",
      "follow_request_sent": false,
      "profile_link_color": "0084B4",
      "is_translator": false,
      "id_str": "6253282",
      "entities": {
        "url": {
          "urls": [
            {
              "expanded_url": null,
              "url": "",
              "indices": [
                0,
                22
              ]
            }
          ]
        },
        "description": {
          "urls": [

          ]
        }
      },

function analyze(data) {
  for (var i = 0; i < data.length; i++) {
    tweet = data[i]['text'];
    tweet = tweet.replace('#' , '');
    return console.log(tweet);
  }
}

module.exports.analyze = analyze;

我当前的代码如下所示：

    [
  {
    "coordinates": null,
    "favorited": false,
    "truncated": false,
    "created_at": "Wed Aug 29 17:12:58 +0000 2012",
    "id_str": "240859602684612608",
    "entities": {
      "urls": [
        {
          "expanded_url": "/blog/twitter-certified-products",
          "url": "",
          "indices": [
            52,
            73
          ],
          "display_url": "
        }
      ],
      "hashtags": [

      ],
      "user_mentions": [

      ]
    },
    "in_reply_to_user_id_str": null,
    "contributors": null,
    "text": "Introducing the Twitter Certified Products Program: ",
    "retweet_count": 121,
    "in_reply_to_status_id_str": null,
    "id": 240859602684612608,
    "geo": null,
    "retweeted": false,
    "possibly_sensitive": false,
    "in_reply_to_user_id": null,
    "place": null,
    "user": {
      "profile_sidebar_fill_color": "DDEEF6",
      "profile_sidebar_border_color": "C0DEED",
      "profile_background_tile": false,
      "name": "Twitter API",
      "profile_image_url": ",
      "created_at": "Wed May 23 06:01:13 +0000 2007",
      "location": "San Francisco, CA",
      "follow_request_sent": false,
      "profile_link_color": "0084B4",
      "is_translator": false,
      "id_str": "6253282",
      "entities": {
        "url": {
          "urls": [
            {
              "expanded_url": null,
              "url": "",
              "indices": [
                0,
                22
              ]
            }
          ]
        },
        "description": {
          "urls": [

          ]
        }
      },

function analyze(data) {
  for (var i = 0; i < data.length; i++) {
    tweet = data[i]['text'];
    tweet = tweet.replace('#' , '');
    return console.log(tweet);
  }
}

module.exports.analyze = analyze;

功能分析（数据）{
对于（变量i=0；i

目前，我在分析功能的输出中只收到一条tweet。我做错了什么

---

多谢各位

您发布的响应不是有效的JSON，您可以再次检查它吗？

要提取包含所有twitts文本的数组，而不包含

。

，您可以执行以下操作：

function analyze(data) {
    return data.map(function(item) {
        return item.text.replace('#' , '');
    });
}

module.exports.analyze = analyze;

---

您正在返回console.log（）

Return语句暂停函数的执行。只需删除return语句，如下所示：

function analyze(data) {
  for (var i = 0; i < data.length; i++) {
    tweet = data[i]['text'];
    tweet = tweet.replace('#' , '');
    console.log(tweet);
  }
}

module.exports.analyze = analyze;

功能分析（数据）{
对于（变量i=0；i

---

如果你想返回函数的结果，你必须将它们存储在for循环之外的一个变量中，在每次迭代时用tweet将其压缩，然后返回该值。

response

JSON

无效。我知道它不是JSON。它似乎是一组物体。