Javascript 使用AJAX请求OAuth2令牌
我正在尝试使用AJAX请求令牌。这将仅在本地主机上用于发出请求。我有密码:Javascript 使用AJAX请求OAuth2令牌,javascript,jquery,ajax,oauth-2.0,Javascript,Jquery,Ajax,Oauth 2.0,我正在尝试使用AJAX请求令牌。这将仅在本地主机上用于发出请求。我有密码: $.ajax({ url: "TOKEN URL HERE", beforeSend: function(xhr) { xhr.setRequestHeader("grant_type", "client_credentials"); xhr.setRequestHeader("client_id", "ENTER CLIENT ID"); xhr.setRequestHeader("cl
$.ajax({
url: "TOKEN URL HERE",
beforeSend: function(xhr) {
xhr.setRequestHeader("grant_type", "client_credentials");
xhr.setRequestHeader("client_id", "ENTER CLIENT ID");
xhr.setRequestHeader("client_secret", "ENTER CLIENT SECRET");
xhr.setRequestHeader("Content-Type", "application/json");
xhr.setRequestHeader("Accept", "application/json");
},
dataType: "json",
//content-Type: "application/json",
type: "POST",
success: function(response) {
token = response.access_token;
expiresIn = response.expires_in;
},
error: function(errorThrown) {
alert(errorThrown.error);
}
});
但是,它不起作用。这是正确的方法还是参数不正确?(或者OAuth2令牌请求在AJAX/JQuery/JS中是不可能的)您确定,授权类型、客户机id、客户机机密应该通过头而不是负载传递吗 尝试从标题中删除它们(左接受,仅限内容类型),然后添加“数据”属性和其余参数 诸如此类:
$.ajax({
url: "TOKEN URL HERE",
beforeSend: function(xhr) {
xhr.setRequestHeader("Content-Type", "application/json");
xhr.setRequestHeader("Accept", "application/json");
},
dataType: "json",
data: {
client_id: "ENTER CLIENT ID",
client_secret: "ENTER CLIENT SECRET",
grant_type: "client_credentials"
},
type: "POST",
success: function(response) {
token = response.access_token;
expiresIn = response.expires_in;
},
error: function(errorThrown) {
alert(errorThrown.error);
}
});
Piotr p的答案对我不起作用。当作为数据的一部分发送时,我从中获取令牌的客户端未接受客户端id和凭据。我不得不使用基本身份验证。这就是对我有效的ajax调用
$.ajax({
"type": "POST",
"url": "https://some.domain.com/oath/token",
"headers": {
"Accept": "application/json",
"Authorization": "Basic " + btoa(username + ":" + password)
},
"data": {
"grant_type": "client_credentials"
},
"success": function(response) {
token = response.access_token;
expiresIn = response.expires_in;
},
"error": function(errorThrown) {
alert(JSON.stringify(errorThrown.error()));
}
});
如果对你有用,请检查一下