Javascript 在TypeScript中将arrow函数声明为return
我想编写一个TypeScript声明,用于导出:Javascript 在TypeScript中将arrow函数声明为return,javascript,typescript,meteor,return-value,arrow-functions,Javascript,Typescript,Meteor,Return Value,Arrow Functions,我想编写一个TypeScript声明,用于导出: export default function connect(options) { let expandedOptions = options; if (typeof options === 'function') { expandedOptions = { getMeteorData: options, }; } const { getMeteorData, pure = true } = exp
export default function connect(options) {
let expandedOptions = options;
if (typeof options === 'function') {
expandedOptions = {
getMeteorData: options,
};
}
const { getMeteorData, pure = true } = expandedOptions;
const BaseComponent = pure ? ReactPureComponent : ReactComponent;
return (WrappedComponent) => (
class ReactMeteorDataComponent extends BaseComponent {
...
}
);
}
通过以下方式将其重新打包为withTracker:
我可以简单地将返回值声明为函数:
declare module 'meteor/react-meteor-data' {
import * as React from 'react';
export function withTracker(func: () => {}): Function;
...
}
如何声明函数创建的参数和返回,而不需要更改原始包中的某些内容?所以我想做一些类似的事情:
export function withTracker(func: () => {}): (React.Component) => { React.Component };
代码的用法如下所示:
import * as React from 'react';
import { withTracker } from 'meteor/react-meteor-data';
class Header extends React.Component<any,any> {
render() {
return "test";
}
}
export default withTracker(() => {
return { user: 1 };
})(Header);
(c: React.Component) => React.Component
import*as React from'React';
从“流星/反应流星数据”导入{withTracker};
类头扩展了React.Component{
render(){
返回“测试”;
}
}
使用跟踪器导出默认值(()=>{
返回{用户:1};
})(标题);
谢谢大家! 您描述的类型可以这样写:
import * as React from 'react';
import { withTracker } from 'meteor/react-meteor-data';
class Header extends React.Component<any,any> {
render() {
return "test";
}
}
export default withTracker(() => {
return { user: 1 };
})(Header);
(c: React.Component) => React.Component
在部分声明模块
:
export function withTracker(func: () => {}): (c: React.Component) => React.Component;
很容易!非常感谢。