从JavaScript中的异步函数返回值?
我有以下代码片段从JavaScript中的异步函数返回值?,javascript,async-await,babeljs,ecmascript-2016,Javascript,Async Await,Babeljs,Ecmascript 2016,我有以下代码片段 "use strict" const req = require('requisition'); async function doRequest () { const url = 'http://api.com/v3/search?q=breno' const res = await req.get(url) console.log(res.status) const body = await res.json(); return "it Wor
"use strict"
const req = require('requisition');
async function doRequest () {
const url = 'http://api.com/v3/search?q=breno'
const res = await req.get(url)
console.log(res.status)
const body = await res.json();
return "it Works!"
}
console.log(doRequest())
请求工作正常,但console.log()生成:
{}
200
而不是
200
"it Works!"
当我尝试:
console.log(await doRequest())
我得到一个
意外的令牌
错误异步
函数返回承诺。在最高层,您必须“订阅”承诺:
doRequest().then(result => console.log(result));