Javascript 用XHR的结果重新填充DataTables表
我使用Jquery DataTables显示一长串记录:Javascript 用XHR的结果重新填充DataTables表,javascript,jquery,datatables,xmlhttprequest,exist-db,Javascript,Jquery,Datatables,Xmlhttprequest,Exist Db,我使用Jquery DataTables显示一长串记录: <table id="mainTable" class="display"> <thead> <tr> <th>ID</th> <th>Date</th>
<table id="mainTable" class="display">
<thead>
<tr>
<th>ID</th>
<th>Date</th>
<th>Sender</th>
<th>Recipient</th>
</tr>
</thead>
<tbody id='mainTableRows'>
<tr><td><td></tr>[etc...]
</tbody>
到目前为止,一切顺利。然后,我希望用户能够使用搜索表单生成新数据。搜索表单类似于:
<form id="advancedSearch" action="modules/advanced_search.xq" method="post" onsubmit="advancedSearch(this);">
如何使用此数据重新填充表?这是我的JavaScript函数,由表单submit调用:
function advancedSearch (oFormElement) {
event.preventDefault()
$('#mainTable').DataTable()
.clear()
.draw();
const oReq = new XMLHttpRequest();
const data = new FormData(oFormElement)
oReq.open("post", oFormElement.action, true);
oReq.send(data);
oReq.onreadystatechange = function () {
if (this.readyState === XMLHttpRequest.DONE && this.status === 200) {
const result = JSON.parse(this.responseText);
if (result == null)
{
document.getElementById("result").innerHTML = "empty"
} else {
$('#mainTable').DataTable( {
ajax: result
} );
}
}
}
}
我遇到无法重新初始化DataTable错误。我甚至尝试“手动”重新填充表格,包括:
for (var i = 0; i < result.length; i++) {
document.getElementById("mainTableRows").innerHTML += '<tr><td>' + result[i].id + '</td><td>' + result[i].dateSent + '</td><td>' + result[i].personSentFullName + '</td><td>' + result[i].personReceivedFullName + '</td><tr>'
我只是得到了一个差异,因为表一直在重新加载旧的“完整”数据,或者我在没有分页的情况下获取了表中的数据,或者其他问题告诉我表没有正确地重新初始化$销毁只是重新加载旧数据,设置serverSide:false也没有帮助。无法重新初始化表,销毁并重新创建表只是浪费处理能力。不要使用JavaScript来执行Ajax请求,而是使用内置的Ajax处理器,这要容易得多。由于您似乎已经在使用内置Ajax来加载表,所以您可以将URL设置为其他URL 常量mainTable=$'mainTable'.DataTable{ 选择权 }; url'modules/advanced_search.xq'.load;
我通过以这种格式返回一个JSON来实现这一点,即在属性名称中使用一个数字序列:
[ {
"0" : "e34712",
"1" : "1768-01-19",
"2" : "Robert Thomas",
"3" : "Richard Morris"
}, {
"0" : "e34716",
"1" : "1768-04-23",
"2" : "Robert Thomas",
"3" : "Richard Morris"
}, {
"0" : "e34779",
"1" : "1768-10-25",
"2" : "Robert Thomas",
"3" : "Richard Morris"
}, {
"0" : "e34805",
"1" : "1769-01-16",
"2" : "Robert Thomas",
"3" : "Richard Morris"
} ]
这是我的工作JavaScript:
"use strict";
function advancedSearch (oFormElement) {
event.preventDefault()
var table = $('#mainTable').DataTable()
table.clear()
if (oFormElement.pe1id.value == '' && oFormElement.pe2id.value == '') {
alert('You have to enter at least one person.');
return false;
} else {
const oReq = new XMLHttpRequest();
const data = new FormData(oFormElement)
oReq.open("post", oFormElement.action, true);
oReq.send(data);
oReq.onreadystatechange = function () {
if (this.readyState === XMLHttpRequest.DONE && this.status === 200) {
const result = JSON.parse(this.responseText);
if (result == null)
{
table.draw()
} else {
{
table.rows.add(result)
table.draw();
}
}
}
}
}
谢谢你的回复。正如我所写的,我最初不是通过Ajax加载表,而是通过eXist db模块加载服务器端。实际上,我只是通过将我的响应JSON返回为[{0:…,1:…,2:…,3:…]来让它工作。想想看吧
[ {
"0" : "e34712",
"1" : "1768-01-19",
"2" : "Robert Thomas",
"3" : "Richard Morris"
}, {
"0" : "e34716",
"1" : "1768-04-23",
"2" : "Robert Thomas",
"3" : "Richard Morris"
}, {
"0" : "e34779",
"1" : "1768-10-25",
"2" : "Robert Thomas",
"3" : "Richard Morris"
}, {
"0" : "e34805",
"1" : "1769-01-16",
"2" : "Robert Thomas",
"3" : "Richard Morris"
} ]
"use strict";
function advancedSearch (oFormElement) {
event.preventDefault()
var table = $('#mainTable').DataTable()
table.clear()
if (oFormElement.pe1id.value == '' && oFormElement.pe2id.value == '') {
alert('You have to enter at least one person.');
return false;
} else {
const oReq = new XMLHttpRequest();
const data = new FormData(oFormElement)
oReq.open("post", oFormElement.action, true);
oReq.send(data);
oReq.onreadystatechange = function () {
if (this.readyState === XMLHttpRequest.DONE && this.status === 200) {
const result = JSON.parse(this.responseText);
if (result == null)
{
table.draw()
} else {
{
table.rows.add(result)
table.draw();
}
}
}
}
}