jdbc可以高效地与其他数据一起获得生成的密钥

在批量插入许多行之后，我希望检索生成的键及其相应的插入行。我如何有效地做到这一点？很自然，我可以使用statement.getGeneratedKeys根据生成的每个id查询数据库中的每一行，但这似乎很慢。下面的代码执行批插入，然后遍历表中的所有结果，但是我不想包含插入前表中已经存在的数据。 还有别的选择吗

public static void main(String[] args) throws Exception { Connection conn = getMySqlConnection(); ResultSet rs = null; Statement stmt = null; try { conn = getMySqlConnection(); stmt = conn.createStatement(ResultSet.TYPE_SCROLL_SENSITIVE, ResultSet.CONCUR_UPDATABLE); conn.setAutoCommit(false); stmt.addBatch("INSERT INTO survey(id, name) VALUES('11', 'Alex')"); stmt.addBatch("INSERT INTO survey(id, name) VALUES('22', 'Mary')"); stmt.addBatch("INSERT INTO survey(id, name) VALUES('33', 'Bob')"); int[] updateCounts = stmt.executeBatch(); System.out.println(updateCounts); conn.commit(); rs = stmt.executeQuery("SELECT * FROM survey"); while (rs.next()) { String id = rs.getString("id"); String name = rs.getString("name"); System.out.println("id="+id +" name="+name); } } catch(BatchUpdateException b) { System.err.println("SQLException: " + b.getMessage()); System.err.println("SQLState: " + b.getSQLState()); System.err.println("Message: " + b.getMessage()); System.err.println("Vendor error code: " + b.getErrorCode()); System.err.print("Update counts: "); int [] updateCounts = b.getUpdateCounts(); for (int i = 0; i < updateCounts.length; i++) { System.err.print(updateCounts[i] + " "); } } catch(SQLException ex) { System.err.println("SQLException: " + ex.getMessage()); System.err.println("SQLState: " + ex.getSQLState()); System.err.println("Message: " + ex.getMessage()); System.err.println("Vendor error code: " + ex.getErrorCode()); } catch(Exception e) { e.printStackTrace(); System.err.println("Exception: " + e.getMessage()); } finally { rs.close(); stmt.close(); conn.close(); } }

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您有一个感兴趣的ID列表。您可以使用“id in…，…，”约束：

StringBuilder newIds = new StringBuilder();
ResultSet rs = stmt.getGeneratedKeys();
while (rs.next()) {
  if (newIds.length() > 0)  newIds.append(',');
  newIds.append(rs.getInt(1));
}

if (newIds.length() > ) {
  rs = stmt.executeQuery("SELECT * FROM survey where id in ("+newIds+")");
  ...
}