Jqgrid 将colName与colModel'；谁的目标？

我编写JQuery是为了在ColumnChooser弹出对话框中获取列的文本，以便获取colModel的名称（或索引），然后我了解到它不是这样工作的，我必须以某种方式对colModel使用colName

问题

colNames: [ 'Id', 'Stock Number', 'VIN', 'Year' ],
colModel: [ 
    { name: 'Id', index: 'Id' },
    { name: 'StockNumber', index: 'StockNumber' }, 
    { name: 'VIN', index: 'VIN' }, 
    { name: 'Year', index: 'Year' }

如您所见，我的问题是，在对$JQGridColumnModel设置使用$ColumnChooserSelectedList时，“StockNumber”与“StockNumber”不同。此外，我无法判断列的顺序是否正确（在colName和colModel之间），因为我不知道它在幕后是如何工作的

 var $ColumnChooserSelectedList = $("#colchooser_test ul.selected li");
 var $ColumnModelSetting = $("#test").jqGrid('getGridParam', 'colModel');
 var returnValue = "";

 $.each($ColumnChooserSelectedList, function (i,o) {
    if (o.title.length > 0) {
       if (returnValue.length > 0) { returnValue += "|"; }
       returnValue += o.title;   //This o.title need to be changed to match colModel's Name (or Index)...
    }
 });

谢谢

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更新-找到解决方案

提出了这个很好的解决方案，但我不能确定它是否100%的时间都有效

 var $ColumnChooserSelectedList = $("#colchooser_test ul.selected li");
 var $ColumnModelSetting = $("#test").jqGrid('getGridParam', 'colModel');
 var $ColumnNameSetting = $("#test").jqGrid('getGridParam', 'colNames');
 var returnValue = "";

 $.each($ColumnChooserSelectedList, function (i1,o1) {
    if (o1.title.length > 0) {
       $.each($ColumnNameSetting, function (i2, o2) {
         if ($ColumnNameSetting[i2] == o1.title) {
            if (returnValue.length > 0) { returnValue += "|"; }
            returnValue += $ColumnModelSetting[i2].name;   
            return false;  //This break the foreach loop...
         }
       });     
    }
 });

 var $ColumnChooserSelectedList = $("#colchooser_test ul.selected li");
 var $ColumnModelSetting = $("#test").jqGrid('getGridParam', 'colModel');
 var $ColumnNameSetting = $("#test").jqGrid('getGridParam', 'colNames');
 var returnValue = "";

 $.each($ColumnChooserSelectedList, function (i1,o1) {
    if (o1.title.length > 0) {
       $.each($ColumnNameSetting, function (i2, o2) {
         if ($ColumnNameSetting[i2] == o1.title) {
            if (returnValue.length > 0) { returnValue += "|"; }
            returnValue += $ColumnModelSetting[i2].name;   
            return false;  //This break the foreach loop...
         }
       });     
    }
 });

---

更新-找到解决方案

提出了这个很好的解决方案，但我不能确定它是否100%的时间都有效

 var $ColumnChooserSelectedList = $("#colchooser_test ul.selected li");
 var $ColumnModelSetting = $("#test").jqGrid('getGridParam', 'colModel');
 var $ColumnNameSetting = $("#test").jqGrid('getGridParam', 'colNames');
 var returnValue = "";

 $.each($ColumnChooserSelectedList, function (i1,o1) {
    if (o1.title.length > 0) {
       $.each($ColumnNameSetting, function (i2, o2) {
         if ($ColumnNameSetting[i2] == o1.title) {
            if (returnValue.length > 0) { returnValue += "|"; }
            returnValue += $ColumnModelSetting[i2].name;   
            return false;  //This break the foreach loop...
         }
       });     
    }
 });

 var $ColumnChooserSelectedList = $("#colchooser_test ul.selected li");
 var $ColumnModelSetting = $("#test").jqGrid('getGridParam', 'colModel');
 var $ColumnNameSetting = $("#test").jqGrid('getGridParam', 'colNames');
 var returnValue = "";

 $.each($ColumnChooserSelectedList, function (i1,o1) {
    if (o1.title.length > 0) {
       $.each($ColumnNameSetting, function (i2, o2) {
         if ($ColumnNameSetting[i2] == o1.title) {
            if (returnValue.length > 0) { returnValue += "|"; }
            returnValue += $ColumnModelSetting[i2].name;   
            return false;  //This break the foreach loop...
         }
       });     
    }
 });

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请参见上面我提出的解决方案的编辑。希望它能100%的工作。