jqgrid中的外部滤波器

我想使用外部过滤器来过滤jqgrid数据。在我的例子中，使用内置过滤器或搜索框会有点奇怪。我有一个应用程序，其中我将有一个表单，它将接受输入并相应地过滤jgrid数据。我已经实现了代码，它成功地为我提供了过滤数据，但没有在jqgrid中实现。我们在定义jqgrid时指定URL，这里我有另一个URL用于提交过滤表单。在这里，jqgrid中过滤数据和显示数据的URL是不同的。那么，如何在jqgrid中显示过滤后的数据呢。我正在用java Hibernate编写代码

这是“我的过滤器”对话框代码： {

现在，当用户点击“过滤事务”按钮时，我希望重新加载网格。在这里，如果用户选择每月过滤网格，那么它将以月份作为输入，并相应地重新加载网格

这是我的servlet代码：

if(request.getParameter("action").equals("filter")){
           if(login!=null)
            {
                String query=null;
                if("Current_Month".equals(request.getParameter("filter_type")))
                {
                    System.out.println("Current month");
                    int month=cal.get(Calendar.MONTH)+1;
                    int year=cal.get(Calendar.YEAR);
                    System.out.println("Current month is: " +month);
                    query = "from TransactionDetails where  register_id="+hb_id+" and transaction_date>='"+year+"-"+month+"-1' and transaction_date<='"+year+"-"+month+"-31'" ;
                    System.out.println("Current month query is: " +query);

                }
                if("Yearly".equals(request.getParameter("filter_type")))
                {
                    System.out.println("Yearly");
                    int year=Integer.parseInt(request.getParameter("year"));
                    System.out.println("Entered year is: " +year);
                    query = "from TransactionDetails where  register_id="+hb_id+" and transaction_date>='"+year+"-1-1' and transaction_date<='"+year+"-12-31'" ;
                    System.out.println("Yearly query is: " +query);

                }
                if("Monthly".equals(request.getParameter("filter_type")))
                {
                    System.out.println("Monthly");
                    int month=Integer.parseInt(request.getParameter("month"));
                    System.out.println("Entered month is: " +month);
                    int year=cal.get(Calendar.YEAR);
                    query = "from TransactionDetails where  register_id="+hb_id+" and transaction_date>='"+year+"-"+month+"-1' and transaction_date<='"+year+"-"+month+"-31'" ;
                    System.out.println("Current month query is: " +query);
                }
                if("Range".equals(request.getParameter("filter_type")))
                {
                    System.out.println("Range");
                    String from_date=request.getParameter("from");
                    String[] date = from_date.split("/");
                    from_date = date[2]+"-"+date[1]+"-"+date[0];
                    String to_date=request.getParameter("to");
                    date = to_date.split("/");
                    to_date = date[2]+"-"+date[1]+"-"+date[0];
                    System.out.println("Entered range is from " +from_date+" to "+to_date);
                    query = "from TransactionDetails where  register_id="+hb_id+" and transaction_date>='"+from_date+"' and transaction_date<='"+to_date+"'" ;
                    System.out.println("Current month query is: " +query);

                }
                if("category".equals(request.getParameter("filter_type")))
                {
                    System.out.println("Category");
                    String  category =request.getParameter("t_filter_category");
                    System.out.println("Entered category is: "+category);
                    query = "from TransactionDetails where  register_id="+hb_id+" and category='"+category+"'" ;
                    System.out.println("Current month query is: " +query);
                }

我通过数据库获得了正确的输出。但是我不知道如何绑定这些数据，或者说如何在我的jgrid中获取这些数据 这是我的网格

function fillGridOnEvent(){
            $("#Transaction_grid").html("<table id=\"transaction_list\"></table><div id=\"page\"></div>");
           jQuery("#transaction_list").jqGrid({
                url:'http://localhost:8084/HomeBudget/TransactionController?action=show&rid=<%=hb_id%>',
                datatype: "xml",
                height: 300,
                colNames:['ID','Date','Type','Category','Amount','Comments'],
                colModel:[
                    {name:'transaction_id',index:'transaction_id', width:20,sortable:false},
                    {name:'date',index:'date', width:100,sortable:false},
                    {name:'type',index:'type', width:100,sortable:false},
                    {name:'category',index:'category', width:150,sortable:false},
                    {name:'amount',index:'amount', width:100,sortable:false, formatter: 'number'},
                    {name:'comments',index:'comments', width:210,sortable:false}
                ],
                paging: true,
                rowNum:15,
                rowList:[15,30,45],
                pager: $("#page"),
                loadonce:true,
                multiselect: false,
                gridview:true,
                viewrecords:true,
                caption: "Transaction"
              }).navGrid('#page',{edit:false,add:false,del:false},{multipleSearch:true, multipleGroup:true, showQuery: true});  

---

}我不确定我是否正确理解你。但是我的解决方案是我有多年使用jqGrid和Java及C的经验

定义为jqGrid数据返回json的servlet/处理程序 参数化servlet实现过滤器 设置新jqGrid参数从表单字段读取参数

$("#" + table).setGridParam({
    postData:queryString
});

重新加载jqGrid $+table.jqGrid.triggerreloadGrid

$("#" + table).setGridParam({
    postData:queryString
});