Jquery 如何获取拼写检查器响应json solr
URL==>> 我正在学习json格式,如何使用jquery获取此响应我得到了答案,我正在寻找此解决方案Jquery 如何获取拼写检查器响应json solr,jquery,json,solr,Jquery,Json,Solr,URL==>> 我正在学习json格式,如何使用jquery获取此响应我得到了答案,我正在寻找此解决方案 I got my answer, I was looking this solution $.ajax({ url: "http://localhost:8080/solr/Test/suggest", dataType: "json", success: function( data ) { var suggestions =
I got my answer, I was looking this solution
$.ajax({ url: "http://localhost:8080/solr/Test/suggest",
dataType: "json",
success: function( data ) {
var suggestions = (data.spellcheck.suggestions &&
data.spellcheck.suggestions.length > 1) ?
data.spellcheck.suggestions[1].suggestion : [];
for (var d=0; d < suggestions.length; d++) {
var doc = suggestions[d];
}
$.ajax({url:http://localhost:8080/solr/Test/suggest",
数据类型:“json”,
成功:功能(数据){
var建议=(data.spellcheck.suggestions&&
data.spellcheck.suggestions.length>1)?
data.spellcheck.suggestions[1]。suggestion:[];
对于(var d=0;d我得到了答案,我正在寻找这个解决方案
$.ajax({url:http://localhost:8080/solr/Test/suggest",
数据类型:“json”,
成功:功能(数据){
var建议=(data.spellcheck.suggestions&&
data.spellcheck.suggestions.length>1)?
data.spellcheck.suggestions[1]。suggestion:[];
对于(var d=0;d
所有建议值都在doc变量中查看函数;当您访问该url时,它有效地执行与浏览器相同的请求。查看函数;当您访问该url时,它有效地执行与浏览器相同的请求。
I got my answer, I was looking this solution
$.ajax({ url: "http://localhost:8080/solr/Test/suggest",
dataType: "json",
success: function( data ) {
var suggestions = (data.spellcheck.suggestions &&
data.spellcheck.suggestions.length > 1) ?
data.spellcheck.suggestions[1].suggestion : [];
for (var d=0; d < suggestions.length; d++) {
var doc = suggestions[d];
}