Jquery OpenWeatherMapAPI的JSON

Jquery OpenWeatherMapAPI的JSON,jquery,json,weather-api,openweathermap,Jquery,Json,Weather Api,Openweathermap,我正在使用API编写一个简单的单页天气应用程序,但在返回的嵌套JSON对象中遇到了一个循环问题 以下是JSON的一个示例: "cod":"200", "message":0.1986, "city":{ "id":"4781530", "name":"Reston", "coord":{ "lon":-77.3545, "lat":38.9597 }, "country":"United States of America"

我正在使用API编写一个简单的单页天气应用程序,但在返回的嵌套JSON对象中遇到了一个循环问题

以下是JSON的一个示例:

"cod":"200",
"message":0.1986,
"city":{
    "id":"4781530",
    "name":"Reston",
    "coord":{
        "lon":-77.3545,
        "lat":38.9597
    },
    "country":"United States of America",
    "population":0
},
"cnt":2,
"list":[
    {
        "dt":1416499200,
        "temp":{
            "day":45.3,
            "min":33.48,
            "max":52,
            "night":34.47,
            "eve":50.59,
            "morn":33.48
        },
        "pressure":1015.56,
        "humidity":58,
        "weather":[
            {
                "id":801,
                "main":"Clouds",
                "description":"few clouds",
                "icon":"02d"
            }
        ],
        "speed":9.07,
        "deg":212,
        "clouds":24
    },
    {
        "dt":1416585600,
        "temp":{
            "day":33.04,
            "min":20.55,
            "max":38.86,
            "night":22.87,
            "eve":38.03,
            "morn":24.42
        },
        "pressure":1027.28,
        "humidity":50,
        "weather":[
            {
                "id":800,
                "main":"Clear",
                "description":"sky is clear",
                "icon":"01d"
            }
        ],
        "speed":7.99,
        "deg":301,
        "clouds":0
    }
]
}

我能够成功循环obj.list中的第一组值,但是当它到达
$时,我得到一个未定义的错误。每个(obj.list[I].weather[I],函数(键,值)
循环

我将如何循环嵌套的weather和temp对象,以及为什么我当前的代码给了我一个未定义的错误?我已经包含了代码和Firebug控制台日志。如果有任何帮助,将不胜感激

jQuery循环函数

$.each(obj.list, function(i) {
    $.each(obj.list[i], function(key,value) {

        if(typeof value == "object"){
            console.log(key + " is an Object!!");

            if(key=="weather"){
                            console.log("What is i? " + i );
                            console.log(obj.list[i].weather[i]);

                            $.each(obj.list[i].weather[i], function(key,value) {
                                    console.log("weather object " + key + ": " + value );
                            });
            }

        }
        else{
            console.log("outer object " + key + ": " + value );
        }
    });
});
Firebug控制台日志:

outer object dt: 1416499200
scripts.js (line 72)
temp is an Object!!
scripts.js (line 49)
outer object pressure: 1015.56
scripts.js (line 72)
outer object humidity: 58
scripts.js (line 72)
weather is an Object!!
scripts.js (line 49)
What is i? 0
scripts.js (line 59)
Object { id=801, main="Clouds", description="few clouds", more...}
scripts.js (line 60)
weather object id: 801
scripts.js (line 66)
weather object main: Clouds
scripts.js (line 66)
weather object description: few clouds
scripts.js (line 66)
weather object icon: 02d
scripts.js (line 66)
outer object speed: 9.07
scripts.js (line 72)
outer object deg: 212
scripts.js (line 72)
outer object clouds: 24
scripts.js (line 72)
***********
scripts.js (line 103)
outer object dt: 1416585600
scripts.js (line 72)
temp is an Object!!
scripts.js (line 49)
outer object pressure: 1027.28
scripts.js (line 72)
outer object humidity: 50
scripts.js (line 72)
weather is an Object!!
scripts.js (line 49)
What is i? 1
scripts.js (line 59)
undefined

您只需要每个
obj.list[i].weather
list中的
i
th元素。您应该在
obj.list[i].weather上循环,而不是从中请求单个元素。因此,对于
obj.list[0]
,您只需要
obj.list[0].weather[0]
.for
obj.list[1]
,您只要求
obj.list[1].weather[1]
,它不存在(该
weather
列表在索引
0
处只有一个对象)

你的
$.each(obj.list[i].weather[i],…)
循环
obj.list[i].weather[i]
,但你不循环
obj.list[i].weather
。你想要的是带有两个不同循环变量的东西,比如
obj.list[i].weather[j]
,而不是
obj.list[i].weather[i]

    if(typeof value == "object"){
        console.log(key + " is an Object!!");

        if(key=="weather"){
                console.log("What is i? " + i );

                $.each(obj.list[i].weather, function(j) {
                    console.log(obj.list[i].weather[j]);
                    $.each(obj.list[i].weather[j], function(key,value) {
                        console.log("weather object " + key + ": " + value );
                    });
                });
        }

    }
在这里,我们使用内部loping变量
j
obj.list[i].weather
上添加了一个循环,这样我们就可以得到每个
weather
列表中的所有项,而不是一项