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使用jquery和ajax加载带有数据库值的select_Jquery_Ajax - Fatal编程技术网

使用jquery和ajax加载带有数据库值的select

使用jquery和ajax加载带有数据库值的select,jquery,ajax,Jquery,Ajax,我正在使用jquery为select选项添加一个div var div_secretary = div_secretary + '<div>Secretary:'; var div_secretary = div_secretary + '<select style="margin-left:5px;" id="select_reviewer_secretary" >'; var div_secretary = div_secretary + '<option>

我正在使用jquery为select选项添加一个div

var div_secretary = div_secretary + '<div>Secretary:';
var div_secretary = div_secretary + '<select style="margin-left:5px;" id="select_reviewer_secretary" >';
var div_secretary = div_secretary + '<option>-select-</option>';
var div_secretary = div_secretary + '</select></div>
当我加载页面时,我得到的json值如下

{"value":[{"CODE":"3621","SUBCODE":"4"},{"CODE":"1561","SUBCODE":"1"}]}
下面是如何将这些值加载到选择选项中。
提前感谢

更改PHP代码或jQuery代码

我建议更改PHP代码,将最后一行更改为:

echo json_encode($tac_Secretaries);

但是如何将该值加载到选项中您正在
getJSON
中正确使用它。只需使用,
item.code
&
item.SUBCODE
我正在获取db值。但它无法加载到选项中。将db的响应发布到此处[{“code”:“3621”,“SUBCODE”:“4”},{“code”:“1561”,“SUBCODE”:“1”}]
{"value":[{"CODE":"3621","SUBCODE":"4"},{"CODE":"1561","SUBCODE":"1"}]}
echo json_encode($tac_Secretaries);