Jquery POST reporting未定义，JSON解析导致语法错误

这个想法相当简单，我们有一个灰尘模板创建复选框和一些静态复选框

  <div class="span10">
                <table class="table table-condensed">
                <caption class="pull-left">Favorite Cuisines:</caption>
                   <input type="hidden" id="myArray" />
                <tbody>
                    <tr>
                        {#data.cuisines}
                        <td>
                            <label class="checkbox inline">
         <input type="checkbox" name="cuisineFavorites" value="{_id}">{cuisineName}
                            </label>
                        </td>
                        {/data.cuisines}

                    </tr>
                    <tr>
                        <td>
                            <label class="checkbox inline">
                                <input type="checkbox" name="cuisineFavorites" value="name"> blank
                            </label>
                        </td>
                        <td>
                            <label class="checkbox inline">
                                <input type="checkbox" name="cuisineFavorites" value="american"> American
                            </label>
                        </td>
                        <td>
</div> 

{@eq key="userProfile" value=prtName}
<script type="text/javascript">
    var selectedCuisines = [];
    function addCuisine(cuisine) {
    if ($.inArray(cuisine, selectedFavorites) < 0) {
        selectedCuisines.push(cuisine);
        selectedCuisines.sort();
    }
    $("#myArray").val("[" + selectedCuisines.join() + "]");
    }
    function removeCuisine(cuisine) {
    var pos = $.inArray(cuisine, selectedCuisines);
    if (pos > 0) {
        selectedCuisines.splice(pos, 1);
        selectedCuisines.sort();
    }
    $("#myArray").val("[" + selectedCuisines.join() + "]");
    }

    $('input[name^=cuisine]').on("click", function(e) {
        if (this.checked === true) {
        addCuisine(this.value);
        } else {
        removeCuisine(this.value);
        }
    });
    </script>
{/eq}

}

请帮助，不知道为什么它是未定义的，让JSON.parse工作了几次，即使它仍然说未定义发布了一个示例输出

SyntaxError:exports.createProfile的Object.parse（本机）处出现意外标记u

它在这里工作

  Model: {"title":"User Profile","prtName":"userProfile","user":{"_id":"532b781934
  fa1a7411000003","__v":0,"authToken":"","salt":"1387859137798","hashed_password":
  "e704f5c86a696a828fbb976446ee1243690b8917","provider":"local","username":"dw","g
  ivenName":"dw","familyName":"dw"},"data":{"cuisines":[{"_id":"532a4d281053cd042c
  000002","__v":0,"cuisineName":"American"},{"_id":"532a5c591053cd042c000003","__v
  ":0,"cuisineName":"Comfort Food"},{"_id":"532a5c5e1053cd042c000004","__v":0,"cui
  sineName":"Indian"},{"_id":"532a5c681053cd042c000005","__v":0,"cuisineName":"Med
  iterranean"},{"_id":"532a5c701053cd042c000006","__v":0,"cuisineName":"Portuguese
 "},{"_id":"532a5c791053cd042c000007","__v":0,"cuisineName":"Argentinian"}]}}

获取/用户/配置文件/创建200 459ms

未定义 打印一些东西 保存配置文件：{u userId:532b781934fa1a7411000003， _识别号：532b781f34fa1a7411000004， 美食最爱： [532a4d281053cd042c000002， 532a5c591053cd042c000003， 532a5c5e1053cd042c000004]， 特殊数据集：[]， 食品：， officePhone:“”， 用户标题：'} 收藏夹[“532a4d281053cd042c000002”、“532A5C5951053CD042C000003”、“532a5c5e1053cd0” 42c000004“]

但通常只有指纹

---

未定义的打印内容，然后发生上述错误。我最近更新了我安装的klei dust，但这不会影响JSON，不要麻烦使用这种方法跨任何对象发送数据数组。我记得post是如何工作的。Name=本例中的菜系收藏夹对应于每个复选框。“发送为邮件”时选中的任何复选框都将放入名为“收藏夹”的数组中。 在这种情况下，当我们创建一个新的配置文件并将req.body设置为该配置文件时，该配置文件会将cuisineFavorites设置为上一页上选择的任意选项

  Model: {"title":"User Profile","prtName":"userProfile","user":{"_id":"532b781934
  fa1a7411000003","__v":0,"authToken":"","salt":"1387859137798","hashed_password":
  "e704f5c86a696a828fbb976446ee1243690b8917","provider":"local","username":"dw","g
  ivenName":"dw","familyName":"dw"},"data":{"cuisines":[{"_id":"532a4d281053cd042c
  000002","__v":0,"cuisineName":"American"},{"_id":"532a5c591053cd042c000003","__v
  ":0,"cuisineName":"Comfort Food"},{"_id":"532a5c5e1053cd042c000004","__v":0,"cui
  sineName":"Indian"},{"_id":"532a5c681053cd042c000005","__v":0,"cuisineName":"Med
  iterranean"},{"_id":"532a5c701053cd042c000006","__v":0,"cuisineName":"Portuguese
 "},{"_id":"532a5c791053cd042c000007","__v":0,"cuisineName":"Argentinian"}]}}