Jquery 如何从jqgrid的Web服务响应中读取jqgrid中的额外数据

我是jQgrid的新手。MyWebService在JSON响应jQgrid时提供除页面、总计、记录和行之外的列数据类型的附加数据。我的JSON字符串如下所示：

{"d":
{"__type":"iReg.JQGrid","page":1,"total":20,"records":194,
"rows":[{"id":"560013cb-9c86-4471-8379-031cea98c507","cell":["TENDERSTATUS","Won - PO Received",""]},
{"id":"88170912-1b2a-441f-9002-0be93e0bcd8f","cell":["ORDERTYPE","Development","Development order"]},
{"id":"e67284f7-4f42-456b-b1a9-04cabaf77305","cell":["ORDERSTATUS","Pending","Pending - Default status"]},
{"id":"14ba5274-e60d-441a-887b-0a999f5a4e4c","cell":["ITEMPROCESS_STEP","Blend","Blending Process"]},
{"id":"aa7857a7-de94-42bf-8075-0ab3d3d65bf1","cell":["EXPENSE_SUBTYPE","Stationary","Stationary"]},
{"id":"b0ab6cd8-4e21-4350-8970-03cd4aaa6d61","cell":["EXPENSE_SUBTYPE","Food","Food"]},
{"id":"57a36caa-01f8-489f-b469-0a803d25c1c6","cell":["DOCUMENT_CATEGORY","Acceptance Note","Acceptance Note"]},
{"id":"9d39f81e-a524-49e8-a0b5-09a865533913","cell":["DESIGNATION","Sales Engineer","Sales Engineer"]},
{"id":"880a2441-e0db-4cda-978c-01387c969df6","cell":["CITY","Noida","U.P."]},
{"id":"0000a8c4-82b8-4ad6-a122-00938307e269","cell":["AIPRIORITY","Medium","Medium priority for action item"]}],
"coldatatypes":["String","String","String"]
}}

在上面的JSON字符串中，coldatatypes是我想在jqgrid中读取的附加数据，我想在其中加入一个变量，以便我可以将其用于其他用途。有可能吗

.cs文件：读取和存储值的属性

   public class JQGrid
   {
      ........
      ........ 
      public List<string> coldatatype { get; set; }
       public JQGrid()
       {
           .......
           coldatatype = new List<string>();
       }
    }

公共类JQGrid
{
........
........ 
公共列表coldatatype{get；set；}
公共JQGrid（）
{
.......
coldatatype=新列表（）；
}
}

@Oleg在这里解释了如何正确阅读@CodeDestroyer:您的建议有效。我正在loadComplete中获取额外数据。我得到的任何数据都是数组格式的表中所有列的数据类型。保持这样的支撑。Thanx很多。。