Jquery 从js.haml调用自定义javascript函数

我已经定义了一个javascript函数，用于使用dataTables操作表。我为表提供了自定义列定义，如下所示

setTableStyle = -> 
  columnDefs = [ { "bSearchable": true, "bVisible": true, "aTargets": [ 0, 1, 2, 3 ] }, { "bSortable": false, "bSearchable": false, "bVisible": true, "aTargets": [ 4 ] } ]

  $('#agents_list, #search_list').dataTable
    'bFilter': false
    'bAutoWidth': false
    'aaSorting': [[ 3, 'desc' ]]
    'bPaginate': false
    'aoColumnDefs': columnDefs

我正在使用“fnDraw”在js.haml文件中重新绘制表，以ajax轮询Agent n中的更改。js.haml代码如下

$('#agents_list').replaceWith("#{escape_javascript(render partial: 'agents_table', locals: {agents: @agents, id: 'agents_list'})}");
var columnDefs = [{"bSearchable": true, "bVisible": true, "aTargets": [0, 1, 2, 3] }, {"bSortable": false,"bSearchable": false, "bVisible": true, "aTargets": [4]}];
var oTable = $('#agents_list').dataTable({ 'bFilter': false, 'bAutoWidth': false, 'aaSorting': [[3, 'desc']], 'bPaginate': false, 'aoColumnDefs': columnDefs});
oTable.fnDraw();

@setTableStyles ->
  #code goes here.

---

我无法从js.haml调用“setTableStyle”，因此我必须重复代码。如何避免这种情况？

在controller\u name.js.coffee文件中将函数声明为全局函数。coffeescript代码如下所示

$('#agents_list').replaceWith("#{escape_javascript(render partial: 'agents_table', locals: {agents: @agents, id: 'agents_list'})}");
var columnDefs = [{"bSearchable": true, "bVisible": true, "aTargets": [0, 1, 2, 3] }, {"bSortable": false,"bSearchable": false, "bVisible": true, "aTargets": [4]}];
var oTable = $('#agents_list').dataTable({ 'bFilter': false, 'bAutoWidth': false, 'aaSorting': [[3, 'desc']], 'bPaginate': false, 'aoColumnDefs': columnDefs});
oTable.fnDraw();

@setTableStyles ->
  #code goes here.

这个函数可以在任何地方调用。在js.haml中

setTableStyles();