Jsf 2 Spring安全自定义表单总是失败
我试图使用SpringSecurity为我的网站（使用JSF2创建）提供一个自定义登录。当我使用默认登录表单时，网站运行良好。但是，当我尝试使用自己的自定义登录表单时，即使键入了正确的用户名/密码，我也总是会被指向身份验证失败url。有人知道这是为什么，或者我如何解决它吗？我的代码如下 security-config.xmlJsf 2 Spring安全自定义表单总是失败,jsf-2,spring-security,Jsf 2,Spring Security,我试图使用SpringSecurity为我的网站（使用JSF2创建）提供一个自定义登录。当我使用默认登录表单时，网站运行良好。但是，当我尝试使用自己的自定义登录表单时，即使键入了正确的用户名/密码，我也总是会被指向身份验证失败url。有人知道这是为什么，或者我如何解决它吗？我的代码如下 security-config.xml <?xml version="1.0" encoding="UTF-8"?> <beans:beans xmlns:sec="http://www.spr
<?xml version="1.0" encoding="UTF-8"?>
<beans:beans
xmlns:sec="http://www.springframework.org/schema/security"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:beans="http://www.springframework.org/schema/beans"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.1.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security-3.1.xsd">
<sec:http auto-config="true" use-expressions="true">
<sec:intercept-url pattern="/login.jsf" access="isAnonymous()" />
<sec:intercept-url pattern="/pages/secure/**" access="hasRole('ROLE_USER')" />
<sec:intercept-url pattern="/pages/home/**" access="hasRole('ROLE_USER')" />
<sec:intercept-url pattern="/pages/unsecure/**" access="permitAll"/>
<sec:form-login login-page="/login.jsf" default-target-url="/pages/home/home.jsf"
authentication-failure-url="/fail.jsf"/>
</sec:http>
<sec:authentication-manager alias="authenticationManager">
<sec:authentication-provider>
<sec:user-service>
<sec:user authorities="ROLE_USER" name="admin" password="admin" />
</sec:user-service>
</sec:authentication-provider>
</sec:authentication-manager>
</beans:beans>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html xmlns="http://www.w3.org/1999/xhtml"
xmlns:f="http://java.sun.com/jsf/core"
xmlns:h="http://java.sun.com/jsf/html"
xmlns:p="http://primefaces.org/ui"
xmlns:ui="http://java.sun.com/jsf/facelets">
<h:head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1" />
<meta http-equiv="Cache-Control" content="no-cache, no-store, must-revalidate" />
<meta http-equiv="Pragma" content="no-cache" />
<meta http-equiv="Expires" content="0" />
<title>Login</title>
<h:outputStylesheet name="css/styles.css" />
<h:outputScript name="jquery/jquery-plugins.js" library="primefaces" />
</h:head>
<h:body>
<div class="login">
<form method="POST" action="j_spring_security_check">
<h:inputText name="j_username" id="username"></h:inputText>
<p:watermark for="username" value="Username" />
<br />
<h:inputSecret name="j_password" id="password">
</h:inputSecret>
<p:watermark for="password" value="Password" />
<br />
<h:commandButton name="submit" type="submit" value="Submit"></h:commandButton>
</form>
</div>
</h:body>
</html>
登录
action=“#{request.contextPath}/j_spring\u security\u check”action=“#{request.contextPath}/j#u spring\u security\u check”名称<h:inputText name="j_username" id="username"></h:inputText>
<h:inputSecret name="j_password" id="password"></h:inputSecret>
<input type="text" name="j_username" placeholder="Username" />
<input type="password" name="j_password" placeholder="Password" />
您是否查看了生成的HTML输出？在浏览器中右键单击页面，不查看源代码即可查看该页面 的
名称<h:inputText name="j_username" id="username"></h:inputText>
<h:inputSecret name="j_password" id="password"></h:inputSecret>
<input type="text" name="j_username" placeholder="Username" />
<input type="password" name="j_password" placeholder="Password" />