在输出中使用带有数组索引的Jq展平JSON
我正在尝试基于嵌套json创建单个json输出:在输出中使用带有数组索引的Jq展平JSON,json,jq,flatten,Json,Jq,Flatten,我正在尝试基于嵌套json创建单个json输出: { "Id" : "1", "items" : [ {"item_name" : "shirt","value" : 10}, {"item_name" : "dress","value" : 20}, {
{
"Id" : "1",
"items" : [
{"item_name" : "shirt","value" : 10},
{"item_name" : "dress","value" : 20},
{"item_name" : "ice cream","value" : 30}
]
}
我的预期产出是:
[
{
"id": "1",
"item_name": "shirt",
"value": 10,
"index_position": 0
},
{
"id": "1",
"item_name": "dress",
"value": 20,
"index_position": 1
},
{
"id": "1",
"item_name": "ice cream",
"value": 30,
"index_position": 2
}
]
我能够获取的唯一输出是此代码段:
迭代内部数组并同时获取外部对象数据的最佳方法是什么?Q.E.D.如下所示:
.Id as $Id
| .items
| [ range(0; length) as $index_position
| {$Id} + .[$index_position] + {$index_position} ]
这里简洁(或至少干练)的关键是jq表达式{$x}
扩展为{“x”:$x}