JSONObject累加和put之间有什么区别？

我已经涉猎了JSON，我在文档（JAVA）中看到，JSONObject的put（）和acculate（）几乎做了相同的事情

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这是关于什么的？

我看到了JSONObject的Java源代码，accumulate和put之间的区别在于，使用accumulate（字符串键，对象值），如果“键”存在一些值，则检查对象是否为数组，如果是数组，则检查“值”将添加到数组中，否则将为此键创建一个数组

但是，在put中，如果键存在，它的值将替换为值-“value”

这是JSONObject累加的来源（字符串键、对象值）

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你用的是哪一个库？android一个，有什么不同吗？所以，如果我需要创建一个简单的一级json对象，它在性能方面更好，是累积还是放置？@HamzehSoboh我认为放置会更好，但除非你的对象很大，否则我认为不会有很大的性能差异。

/**
 * Appends {@code value} to the array already mapped to {@code name}. If
 * this object has no mapping for {@code name}, this inserts a new mapping.
 * If the mapping exists but its value is not an array, the existing
 * and new values are inserted in order into a new array which is itself
 * mapped to {@code name}. In aggregate, this allows values to be added to a
 * mapping one at a time.
 *
 * <p> Note that {@code append(String, Object)} provides better semantics.
 * In particular, the mapping for {@code name} will <b>always</b> be a
 * {@link JSONArray}. Using {@code accumulate} will result in either a
 * {@link JSONArray} or a mapping whose type is the type of {@code value}
 * depending on the number of calls to it.
 *
 * @param value a {@link JSONObject}, {@link JSONArray}, String, Boolean,
 *     Integer, Long, Double, {@link #NULL} or null. May not be {@link
 *     Double#isNaN() NaNs} or {@link Double#isInfinite() infinities}.
 */

  public JSONObject accumulate(String name, Object value) throws JSONException {
    Object current = nameValuePairs.get(checkName(name));
    if (current == null) {
        return put(name, value);
    }

    if (current instanceof JSONArray) {
        JSONArray array = (JSONArray) current;
        array.checkedPut(value);
    } else {
        JSONArray array = new JSONArray();
        array.checkedPut(current);
        array.checkedPut(value);
        nameValuePairs.put(name, array);
    }
    return this;
}

 /**
 * Maps {@code name} to {@code value}, clobbering any existing name/value
 * mapping with the same name.
 *
 * @return this object.
 */
public JSONObject put(String name, boolean value) throws JSONException {
    nameValuePairs.put(checkName(name), value);
    return this;
}