Xcode-推送通知Json
我想以包含自定义数据的Json格式向我的应用程序发送推送通知,但我不知道如何从中提取数据,甚至不知道我的Json格式是否正确。(我认为这是因为Parse成功地发送了它) 来自解析的Json:Xcode-推送通知Json,json,xcode,push-notification,Json,Xcode,Push Notification,我想以包含自定义数据的Json格式向我的应用程序发送推送通知,但我不知道如何从中提取数据,甚至不知道我的Json格式是否正确。(我认为这是因为Parse成功地发送了它) 来自解析的Json: { "aps": { "badge": 1, "alert": "Test", "sound": "" }, "url": "http://www.google.com" } Appdelegate: func applica
{
"aps": {
"badge": 1,
"alert": "Test",
"sound": ""
},
"url": "http://www.google.com"
}
Appdelegate:
func application(application: UIApplication, didReceiveRemoteNotification userInfo: NSDictionary!) {
var notificationPayload: NSDictionary = userInfo["url"] as NSDictionary!
if (notificationPayload["url"] != nil) {
var url = notificationPayload["url"] as String
var feed: FeedTableViewController = navigation.viewControllers[0] as FeedTableViewController
feed.messages.append(url)
feed.sections.append("url")
}else {
PFPush.handlePush(userInfo)
}
}
请尝试以下方法:
func application(application: UIApplication, didReceiveRemoteNotification userInfo: NSDictionary!) {
if let url = userInfo["url"] as? String {
var feed: FeedTableViewController = navigation.viewControllers[0] as FeedTableViewController
feed.messages.append(url)
feed.sections.append("url")
} else {
PFPush.handlePush(userInfo)
}
}
是的,这非常有效,我可以添加我想要的数据吗?例如:“url”、“日期”、“类别”是否也可以在didLaunchWithOptions函数中实现?