使用POST请求将WebApi序列化为Json
我有以下WebApi控制器使用POST请求将WebApi序列化为Json,json,asp.net-core,serialization,swagger,Json,Asp.net Core,Serialization,Swagger,我有以下WebApi控制器 [Route("api/[controller]")] public class FunctionController : ControllerBase { private readonly ILogger<FunctionController> _logger; private readonly IServiceAccessor<IFunctionManagementService> _functionManagementSe
[Route("api/[controller]")]
public class FunctionController : ControllerBase
{
private readonly ILogger<FunctionController> _logger;
private readonly IServiceAccessor<IFunctionManagementService> _functionManagementService;
public FunctionController(
IServiceAccessor<IFunctionManagementService> FunctionManagementService,
ILogger<FunctionController> logger)
{
_functionManagementService = FunctionManagementService;
_logger = logger;
}
[HttpPost]
[SwaggerOperation(nameof(RegisterFunction))]
[SwaggerResponse(StatusCodes.Status200OK, "OK", typeof(FunctionRegisteredResponseDto))]
[SwaggerResponse(StatusCodes.Status400BadRequest, "Bad Request")]
public async Task<IActionResult> RegisterFunction(RegisterFunctionDto rsd)
{
var registeredResponse = await _functionManagementService.Service.RegisterFunctionAsync(rsd);
if (registeredResponse.Id > -1)
return Ok(registeredResponse);
return BadRequest(registeredResponse);
}
[HttpDelete("{id}")]
[SwaggerOperation(nameof(UnregisterFunction))]
[SwaggerResponse(StatusCodes.Status200OK, "OK")]
[SwaggerResponse(StatusCodes.Status404NotFound, "Not Found")]
[SwaggerResponse(StatusCodes.Status400BadRequest, "Bad Request")]
public async Task<IActionResult> UnregisterFunction(string sid)
{
if (!long.TryParse(sid, out long id))
return new BadRequestObjectResult(new { message = "400 Bad Request", UnknownId = sid });
if (!await _functionManagementService.Service.UnregisterFunctionAsync(id))
return new NotFoundObjectResult(new { message = "404 Not Found", UnknownId = sid });
return new OkObjectResult(new { Message = "200 OK", Id = id, Unregistered = true });
}
}
问:如何使用Newtonsoft.Json和post-to-me服务正确序列化对象?如果使用
HttpClient.PostAsync
,则无需创建HttpRequestMessage
。只需构建内容并发送即可
RegisterFunctionDto rsd = Utils.GetRegisterFunctionDtoObject();
string serializedDto = JsonConvert.SerializeObject(rsd);
var content = new StringContent(serializedDto, Encoding.UTF8, "application/json");
HttpResponseMessage response = await client.PostAsync("api/Function", content);
您还可以明确地告诉操作绑定到请求体中的数据
//...
public async Task<IActionResult> RegisterFunction([FromBody]RegisterFunctionDto rsd) {
//...
}
/。。。
公共异步任务注册表函数([FromBody]注册表函数到rsd){
//...
}
RegisterFunctionDto rsd = Utils.GetRegisterFunctionDtoObject();
string serializedDto = JsonConvert.SerializeObject(rsd);
var content = new StringContent(serializedDto, Encoding.UTF8, "application/json");
HttpResponseMessage response = await client.PostAsync("api/Function", content);
//...
public async Task<IActionResult> RegisterFunction([FromBody]RegisterFunctionDto rsd) {
//...
}