在Swift 3中解析JSON(CLLocationCoordinate2D)
我试图用GooglePlacesIOSAPI解析JSON链接。当我打印坐标时,它显示为 CLLocationCoordinate2D(纬度:0.0,经度:0.0) 而不是这个地方的实际坐标。我认为这可能是一个字典/对象问题,但我找不到解决方案 下面是我的JSON解析代码:在Swift 3中解析JSON(CLLocationCoordinate2D),json,swift,google-places-api,Json,Swift,Google Places Api,我试图用GooglePlacesIOSAPI解析JSON链接。当我打印坐标时,它显示为 CLLocationCoordinate2D(纬度:0.0,经度:0.0) 而不是这个地方的实际坐标。我认为这可能是一个字典/对象问题,但我找不到解决方案 下面是我的JSON解析代码: func parseJsonData(data: NSData) -> [GymGooglePlace] { do { typealias JSONDictionary = [String:A
func parseJsonData(data: NSData) -> [GymGooglePlace] {
do {
typealias JSONDictionary = [String:Any]
if let parsedData = try JSONSerialization.jsonObject(with: data as Data) as? JSONDictionary, let gyms = parsedData["results"] as? [JSONDictionary] {
for gym in gyms {
var coordinate = CLLocationCoordinate2D()
var latitude:CLLocationDegrees!
var longitude:CLLocationDegrees!
var maxWidth:Int!
var photoReference:String!
let photoURL:String!
if let geometry = gym["geometry"] as? [JSONDictionary] {
for result in geometry {
if let locations = result["location"] as? [JSONDictionary] {
for location in locations {
latitude = location["lat"] as! CLLocationDegrees!
longitude = location["lng"] as! CLLocationDegrees!
coordinate.latitude = latitude
coordinate.longitude = longitude
}
}
}
}
if let photos = gym["photos"] as? [JSONDictionary] {
for photo in photos {
maxWidth = photo["width"] as! Int!
photoReference = photo["photo_reference"] as! String!
}
}
photoURL = "https://maps.googleapis.com/maps/api/place/photo?maxwidth=\(maxWidth!)&photoreference=\(photoReference!)&key=\(googleAPIKey)"
print(photoURL)
print(coordinate)
print("spacespacespacespacespacespacespacespacespace")
}
}
} catch {
print(error)
}
return gymGooglePlaces
}
键
几何体
和位置
的值是字典,请注意{}
,数组是[]
if let geometry = gym["geometry"] as? JSONDictionary,
let location = geometry["location"] as? JSONDictionary {
coordinate.latitude = location["lat"] as! CLLocationDegrees
coordinate.longitude = location["lng"] as! CLLocationDegrees
}
您的JSON看起来像什么?您是否确保获得了实际的lat和long值,即结果[“location”]实际上包含一些数据?老实说,我过去常常手动解析JSON负载,因此不需要拉入任何第三方库。但现在,我喜欢ObjectMapper或SwiftyJson之类的播客。因此,当JSON有效负载结构发生变化时,您需要做的只是改变键路径,而不是重写解析方法