Python：将多个列表合并到一个JSON数组中

我想将多个列表合并到一个JSON数组中。 以下是我的两份清单：

address =  ['address1','address2']
temp = ['temp1','temp2']

我通过下面的调用合并了这两个列表，并创建了一个JSON

new_list = list(map(list, zip(address, temp)))
jsonify({
    'data': new_list
})

这是我的通话结果：

{
    "data": [
        [
            "address1",
            "temp1"
        ],
        [
            "address2",
            "temp2"
        ]
    ]
}

然而，我想收到以下问题。如何操作以及如何插入标识符

地址

和

你好

{
    "data": [
        {
            "address": "address1",
            "temp": "temp1"
        },
        {
            "address": "address2",
            "temp": "temp2"
        }
    ]
}

---

您可以使用列表：

import json

address =  ['address1','address2']
temp = ['temp1','temp2']

d = {'data': [{'address': a, 'temp': t} for a, t in zip(address, temp)]}

print( json.dumps(d, indent=4) )

印刷品：

{
    "data": [
        {
            "address": "address1",
            "temp": "temp1"
        },
        {
            "address": "address2",
            "temp": "temp2"
        }
    ]
}

---

您可以使用列表：

import json

address =  ['address1','address2']
temp = ['temp1','temp2']

d = {'data': [{'address': a, 'temp': t} for a, t in zip(address, temp)]}

print( json.dumps(d, indent=4) )

印刷品：

{
    "data": [
        {
            "address": "address1",
            "temp": "temp1"
        },
        {
            "address": "address2",
            "temp": "temp2"
        }
    ]
}

---

您可以像这样更改现有代码。该

lambda

函数将实现将其转换为dict的技巧

address =  ['address1','address2']
temp = ['temp1','temp2']

new_list = list(map(lambda x : {'address': x[0], 'temp': x[1]}, zip(address, temp)))

jsonify({
    'data': new_list
})

---

您可以像这样更改现有代码。该

lambda

函数将实现将其转换为dict的技巧

address =  ['address1','address2']
temp = ['temp1','temp2']

new_list = list(map(lambda x : {'address': x[0], 'temp': x[1]}, zip(address, temp)))

jsonify({
    'data': new_list
})

---

很酷，很简单。我本来可以自己想出来的。非常感谢你的帮助。真的很棒，很酷很简单。我本来可以自己想出来的。非常感谢你的帮助。真的很好。