如何在laravel-8中从另一个表中的表调用id

这里我有三个表，分别命名为

user

，

product

，

project

在

项目表

中，我有两个异化名称

用户id

和

产品id

我想在

ProjectController.php

在这里，我可以在index方法中调用user\u id，但我不能调用product\u id。谢谢您的帮助 这是我在ProjectController.php中的索引方法

如何在何处写入产品标识？我无法获取产品id值

public function index()
{
$projects = Project::where('user_id',auth()->user()->id)->where('product_id')->latest()           ->paginate(20);
return view('projects.index', compact('projects'))
       ->with('i', (request()->input('page', 1) - 1) * 5);
}

这是products table products.php

 Schema::create('products', function (Blueprint $table) {
            $table->bigIncrements('id');
            $table->string('name');
            $table->text('detail');
            $table->string('color');
            $table->string('image');
            $table->string('logo');
            $table->unsignedBigInteger('user_id');
            $table->timestamps();
            $table->foreign('user_id')->references('id')->on('users')->onDelete('cascade');
        });

这是projects表projects.php

 Schema::create('projects', function (Blueprint $table) {
            $table->bigIncrements('id');
            $table->string('chapter_name', 255)->nullable();
            $table->string('sub_section_name', 500)->nullable();
            $table->string('title_1', 255)->nullable();
            $table->string('description_1', 5000)->nullable();
            $table->string('image_1', 255)->nullable();
            $table->string('image_2', 255)->nullable();
            $table->string('image_3', 255)->nullable();
            $table->string('title_2', 255)->nullable();
            $table->string('description_2', 5000)->nullable();
            $table->string('title_3', 255)->nullable();
            $table->string('description_3', 255)->nullable();
            $table->string('video_1', 255)->nullable();
            $table->string('video_2', 255)->nullable();
            $table->string('video_3', 255)->nullable();
            $table->unsignedBigInteger ('user_id');
            $table->foreign('user_id')->references('id')->on('users')->onDelete('cascade');
            // $table->foreignId('product_id')->nullable();
            $table->unsignedBigInteger('product_id')->references('id')->on('products')->onDelete('cascade');
            $table->timestamp('created_at')->useCurrent();
            $table->timestamp('updated_at')->nullable();
        });

这是ProjetcImport.php

return new Project([
            'chapter_name'     => $row['chapter_name'],
            'sub_section_name'    => $row['sub_section_name'],
            'title_1'    => $row['title_1'],
            'description_1'    => $row['description_1'],
            'image_1'    => $row['image_1'],
            'image_2'    => $row['image_2'],
            'image_3'    => $row['image_3'],
            'title_2'    => $row['title_2'],
            'description_2'    => $row['description_2'],
            'title_3'    => $row['title_3'],
            'description_3'    => $row['description_3'],
            'video_1'    => $row['video_1'],
            'video_2'    => $row['video_2'],
            'video_3'    => $row['video_3'],
            'user_id'    => auth()->user()->id,
            'product_id'    => Product::where('user_id',Auth::id())->pluck('id'))
            // 'product_id' => id()->id
        ]);

---

我希望它能对您起作用。

根据添加的产品id的条件？我不想在这里添加身份验证条件，我只希望produtc id能在项目表中按异化方式工作。它将采用产品id。一对多关系一个产品将具有多个项目和表结构好的，然后获得产品id基于用户id获得它？项目：：其中（'product_id'，products：：where（'user_id'，Auth：：id（））->pulk（'id'）->toArray（）；它的工作我需要更多的帮助我必须在我的projetcImport.php中调用相同的内容你能帮我吗好的，请用表结构添加其他问题。请尝试这个

Project::whereIn('product_id',Products::where('user_id',Auth::id())->pluck('id')->toArray())->latest()->paginate(20);