Linux Bash在多行中匹配字符串并附加到前一行
我正在尝试使用以下行打开文本文件:Linux Bash在多行中匹配字符串并附加到前一行,linux,bash,awk,sed,Linux,Bash,Awk,Sed,我正在尝试使用以下行打开文本文件: policy rule { source-address host1; destination-address host2; application http; policy someotherrule { source-address any; destination-address [ host2 host3]; application ssh; 进入: 因此,基本上,如果一行以分号结尾,则将其附加到前一行
policy rule {
source-address host1;
destination-address host2;
application http;
policy someotherrule {
source-address any;
destination-address [ host2 host3];
application ssh;
进入:
因此,基本上,如果一行以分号结尾,则将其附加到前一行
我一直在玩sed/awk,但还没有找到一个有效的解决方案来获得所需的输出。以下gnu awk应该可以工作:
awk -v RS='(^|\n)[^\n]*[^;]\n' 'NF{s=p $0; gsub(/(^|\n+)[[:blank:]]+/, " ", s); print s}
{p=RT}' file
policy rule { source-address host1; destination-address host2; application http;
policy someotherrule { source-address any; destination-address [ host2 host3]; application ssh;
这个简单的一行程序可以:
perl -p0e 's/\n\s+/ /g' file
policy rule { source-address host1; destination-address host2; application http;
policy someotherrule { source-address any; destination-address [ host2 host3]; application ssh;
以下是一个awk解决方案:
awk '{$1=$1;printf (/^policy/ &&NR>1?RS:"")"%s",$0} END {print ""}' file
policy rule {source-address host1;destination-address host2;application http;
policy someotherrule {source-address any;destination-address [ host2 host3];application ssh;
它根据行是否以策略开始设置更改行的输出。显示您的努力!你试过什么?你有什么疑问?
awk '{$1=$1;printf (/^policy/ &&NR>1?RS:"")"%s",$0} END {print ""}' file
policy rule {source-address host1;destination-address host2;application http;
policy someotherrule {source-address any;destination-address [ host2 host3];application ssh;