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Linux 声明日期变量的Shell脚本_Linux_Shell_Date_Unix - Fatal编程技术网

Linux 声明日期变量的Shell脚本

Linux 声明日期变量的Shell脚本,linux,shell,date,unix,Linux,Shell,Date,Unix,下面是我写的剧本 #!/usr/bin/expect -f #!/bin/bash # connect via scp Y_DATE=`$(date --date yesterday "+%Y-%m-%d")` spawn scp /apps/Train/jboss-soa-p.5.0.0/jboss-as/server/default/log/server.log.$Y_DATE "xxxx@Tdev:/apps/software/copiedLogFiles/" expect "p

下面是我写的剧本

#!/usr/bin/expect -f
#!/bin/bash

# connect via scp

Y_DATE=`$(date --date yesterday "+%Y-%m-%d")`

spawn scp /apps/Train/jboss-soa-p.5.0.0/jboss-as/server/default/log/server.log.$Y_DATE  "xxxx@Tdev:/apps/software/copiedLogFiles/"

expect "password:"
send "buildadmin\$123\r"
expect "*\r"
expect "\r"
在执行脚本时,我得到以下错误

can't read "(date --date yesterday "+%Y-%m-%d")": no such variable
    while executing
"Y_DATE=`$(date --date yesterday "+%Y-%m-%d")`"
    (file "./copySITtoUAT_CDS.sh" line 6)

我无法找出Y_日期声明中的错误是什么?我是不是遗漏了什么。

也许是这样的:你可以用其中一种

Y_DATE=$(date --date yesterday "+%Y-%m-%d")


但不是两者都有。

我修改了我的脚本,如下所示,它成功了

#!/bin/sh

LOG_DIR=/apps/jboss/jboss-soa-p.5.0.0/jboss-as/server/mssql_prod1/log
SRS_HOST=XPSIT
USER_ID=xambas
PSWD=abackc
Y_DIR=`find $LOG_DIR -name "server.log*" \( -mtime -1 -and -not -daystart -mtime 0 \)`
cd $LOG_DIR
Y_FILE=`find . -name "server.log*" \( -mtime -1 -and -not -daystart -mtime 0 \)`
cd -
export Y_FILE SRS_HOST USER_ID PSWD Y_DIR

expect -c '
        spawn scp "$env(Y_DIR)" "$env(USER_ID)@$env(SRS_HOST):/apps/soft/Prod_LOG/Prod_A/$env(Y_FILE)"
        expect "password:"
        send "$env(PSWD)\r"
        expect "*\r"
        expect "\r"

以下代码起作用:

Y_DATE=`date --date yesterday +%Y-%m-%d`
最好是
$()
(在嵌套时简化)。
Y_DATE=`date --date yesterday +%Y-%m-%d`