Loops 阿杜伊诺。计算按下按钮的次数，然后播放顺序

帮我编写这个程序

当我按下按钮一次时，序列s1（）将播放

当我按两次按钮时，序列s2（）将播放

当我三次按下按钮时，序列s3（）将播放

当我按下按钮4次时，序列s4（）将播放

---

//代码
常量int buttonPin=10；
int buttonState=0；
无效设置（）{
Serial.begin（9600）；
//将引脚2-9初始化为输出
对于（int i=2；i你是指类似的东西吗？我使用了内部上拉和按钮作为有源低电平开关，所以我使用了与低电平比较：

const int    btn = 4;
byte  btn_tim_on = 0;
byte btn_tim_off = 0;
byte     btn_val = 0;

void setup() {
  pinMode(btn, INPUT_PULLUP);
  Serial.begin(57600); // debug purposes
}

void loop() {

  if (digitalRead(btn) == LOW) {
    if (++btn_tim_on == 5) {    // 5 checks before it's considered as key press and every 256*4ms repeat
      ++btn_val;
    }
    btn_tim_off = 80;           // about 0.32 second to confirm
  } else {
    btn_tim_on = 0;             // reset button pressed timer
    if (btn_tim_off > 0) {
      if (--btn_tim_off == 1) { // call action
        Serial.println(btn_val); // print in serial monitor
        switch (btn_val) {
          case 1: s1(); break;
          case 2: s2(); break;
          case 3: s3(); break;
          case 4: s4(); break;
          default: Serial.println(F("no action")); break;
        }
      }
    } else {
      btn_val = 0;              // reset button press counter
    }
  }
  delay(4);
}

// where to place s1, s2, s3 and s4 ...
// playing these actions is blocking, so no keys are detected during "play"

你能更好地解释你的问题吗？只是一个提示，你可能会在那里得到更好/更快的帮助…这部分论坛主要用于编程相关问题。因此，请在提问之前阅读，因为这些将帮助你从社区获得更多更好的答案。谢谢！当循环结束时，我按下按钮有没有办法打破循环她在跑步吗？
const int    btn = 4;
byte  btn_tim_on = 0;
byte btn_tim_off = 0;
byte     btn_val = 0;

void setup() {
  pinMode(btn, INPUT_PULLUP);
  Serial.begin(57600); // debug purposes
}

void loop() {

  if (digitalRead(btn) == LOW) {
    if (++btn_tim_on == 5) {    // 5 checks before it's considered as key press and every 256*4ms repeat
      ++btn_val;
    }
    btn_tim_off = 80;           // about 0.32 second to confirm
  } else {
    btn_tim_on = 0;             // reset button pressed timer
    if (btn_tim_off > 0) {
      if (--btn_tim_off == 1) { // call action
        Serial.println(btn_val); // print in serial monitor
        switch (btn_val) {
          case 1: s1(); break;
          case 2: s2(); break;
          case 3: s3(); break;
          case 4: s4(); break;
          default: Serial.println(F("no action")); break;
        }
      }
    } else {
      btn_val = 0;              // reset button press counter
    }
  }
  delay(4);
}

// where to place s1, s2, s3 and s4 ...
// playing these actions is blocking, so no keys are detected during "play"