Macos 如何在分隔符文本文件中搜索和删除图案

我有以下案文：

s:50:“index.php？附件=$matches[1]&cpage=$matches[2]”；s:44:“（雇主条款）/trackback/？$”；s:35：“index.php？pagename=$matches[1]&tb=1”；s:71:“（雇主的条款条件）/feed/（feed | rdf | rss | rss2 | atom | jobman）/？$”；s:47：“index.php？pagename=$matches[1]&提要=$matches[2]”；s:66:“（雇主条款）/（feed | rdf | rss | rss2 | atom | jobman）/？$”；s:47：“index.php？pagename=$matches[1]&提要=$matches[2]”；s:52:“（雇主的条款条件）/page/？（[0-9]{1，}）/？$”；s:48:“index.php？pagename=$matches[1]&paged=$matches[2]”；s:59:“（雇主条款）/评论页-（[0-9]{1，}）/？$”；s:48：“index.php？pagename=$matches[1]&cpage=$matches[2]”；s:44:“（雇主条款）（/[0-9]+）？/？$”；s:47：“index.php？pagename=$matches[1]&page=$matches[2]”；s:26：“主页/附件/（[^/]+）/？$”；s:32：“index.php？附件=$matches[1]”；s:36：“主页/附件/（[^/]+）/trackback/？$”；s:37：“index.php？附件=$matches[1]&tb=1”；s:63：“主页/附件/（[^/]+）/feed/（feed | rdf | rss | rss2 | atom | jobman）/？$”；s:49：“index.php？附件=$matches[1]&提要=$matches[2]”；s:58：“主页/附件/（[^/]）/（提要| rdf | rss | rss2 |原子|作业员）/？$”

我想做的是搜索jobman这个词并删除找到这个词的整个条目。每个条目的分隔符是分号“；”。我需要从Mac OS命令行执行此操作。所以我有grep、fgrep和awk等工具可用
 首先，我们需要从文本中删除什么

$> grep -o -P "[^;]*jobman[^;]*;" ./text 
s:71:"(term-conditions-for-employers)/feed/(feed|rdf|rss|rss2|atom|jobman)/?$";
s:66:"(term-conditions-for-employers)/(feed|rdf|rss|rss2|atom|jobman)/?$";
s:63:"home/attachment/([^/]+)/feed/(feed|rdf|rss|rss2|atom|jobman)/?$";
s:58:"home/attachment/([^/]+)/(feed|rdf|rss|rss2|atom|jobman)/?$";

如果它是正确的，那么

$> sed "s/[^;]*jobman[^;]*;//g" ./text 
s:50:"index.php?attachment=$matches[1]&cpage=$matches[2]";s:44:"(term-conditions-for-employers)/trackback/?$";s:35:"index.php?pagename=$matches[1]&tb=1";s:47:"index.php?pagename=$matches[1]&feed=$matches[2]";s:47:"index.php?pagename=$matches[1]&feed=$matches[2]";s:52:"(term-conditions-for-employers)/page/?([0-9]{1,})/?$";s:48:"index.php?pagename=$matches[1]&paged=$matches[2]";s:59:"(term-conditions-for-employers)/comment-page-([0-9]{1,})/?$";s:48:"index.php?pagename=$matches[1]&cpage=$matches[2]";s:44:"(term-conditions-for-employers)(/[0-9]+)?/?$";s:47:"index.php?pagename=$matches[1]&page=$matches[2]";s:26:"home/attachment/([^/]+)/?$";s:32:"index.php?attachment=$matches[1]";s:36:"home/attachment/([^/]+)/trackback/?$";s:37:"index.php?attachment=$matches[1]&tb=1";s:49:"index.php?attachment=$matches[1]&feed=$matches[2]";

我们在
“s/[^；]*jobman[^；]*；//g”中实际做的是搜索
[^；]*jobman[^；]*一组符号（不是
：
任何时间，
作业人员
，不是
：
任何时间和；）。然后我们将其替换为“”。并对所有文本行进行替换