在MATLAB中拆分数组

我有一个整数数组，我想在0出现的地方拆分这个数组，并用一个函数给我拆分点

示例：数组：0 0 1 2 4 5 6 0 0 0 0 22 4 5 6 6 0 0 0 0 4 4 0

函数必须返回以下数字：

[ 3 10 ;14 20 ;22 25 ]

这些数字是非零数字开始和结束的索引。

试试这个

a = [0 0 0 1 2 4 5 6 6 0 0 0 0 0 22 4 5 6 6 0 0 0 4 4 0];

%#Places where value was zero and then became non-zero
logicalOn = a(1:end-1)==0 & a(2:end)~=0;

%#Places where value was non-zero and then became zero
logicalOff = a(1:end-1)~=0 & a(2:end)==0;

%#Build a matrix to store the results
M = zeros(sum(logicalOn),2);

%#Indices where value was zero and then became non-zero
[~,indOn] = find(logicalOn);

%#Indices where value was non-zero and then became zero
[~,indOff] = find(logicalOff);

%#We're looking for the zero AFTER the transition happened
indOff = indOff + 1;

%#Fill the matrix with results
M(:,1) = indOn(:);
M(:,2) = indOff(:);

%#Display result
disp(M);

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下面是一个简单的矢量化解决方案，使用函数和：

---

关于主题，但略有变化：

>>> a= [0 0 0 1 2 4 5 6 6 0 0 0 0 0 22 4 5 6 6 0 0 0 4 4 0];
>>> adjust= [0 1]';
>>> tmp= reshape(find([0 diff(a== 0)])', 2, [])
tmp =
    4   15   23
   10   20   25
>>> indices= (tmp- repmat(adjust, 1, size(tmp, 2)))'
indices =
    4    9
   15   19
   23   24

正如

gnovice

已经指出的与

索引相关的位置语义，我只想补充一点，使用此解决方案，在计算
索引时，可以非常直接地处理各种方案。因此，应你的要求：

>>> adjust= [1 0]';
>>> tmp= reshape(find([0 diff(a== 0)])', 2, []);
>>> indices= (tmp- repmat(adjust, 1, size(tmp, 2)))'
indices =
    3   10
   14   20
   22   25

@amro-这更像是OP试图找到非零值孤岛的问题的倒数。@Kev：要转换为另一个，只需添加
array=（array==0）
在开始时（或者从另一个角度看，
array~=0
，这取决于你看它的方式）.@amro-true，但它不是一个“精确”的重复项。@Kev:我想我应该称它为
重复答案
，而不是
重复问题
：）相关问题：
>>> a= [0 0 0 1 2 4 5 6 6 0 0 0 0 0 22 4 5 6 6 0 0 0 4 4 0];
>>> adjust= [0 1]';
>>> tmp= reshape(find([0 diff(a== 0)])', 2, [])
tmp =
    4   15   23
   10   20   25
>>> indices= (tmp- repmat(adjust, 1, size(tmp, 2)))'
indices =
    4    9
   15   19
   23   24

>>> adjust= [1 0]';
>>> tmp= reshape(find([0 diff(a== 0)])', 2, []);
>>> indices= (tmp- repmat(adjust, 1, size(tmp, 2)))'
indices =
    3   10
   14   20
   22   25