Matplotlib 比较重新排列中的行

我有一个csv文件，看起来像这样

time,a1,a2,a3,a4,a5
0,0.0598729227761,0.0598729227761,0.0,-0.0598729227761
1,0.0598729227761,0.0598729227761,0.0,-0.0598729227761
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8,0.0,-0.0598729227761,0.0,-0.0598729227761
9,0.0,-0.0598729227761,0.0,-0.0598729227761
10,0.0,-0.0598729227761,0.0,-0.0598729227761
11,0.0,-0.0598729227761,0.0,-0.0598729227761
12,0.0,0.179618768328,-0.0598729227761,-0.0598729227761
13,0.0,0.179618768328,-0.0598729227761,-0.0598729227761
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16,0.0,0.179618768328,-0.0598729227761,-0.0598729227761
17,0.0,0.179618768328,-0.0598729227761,-0.0598729227761
18,0.0,0.179618768328,-0.0598729227761,-0.0598729227761
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81,0.0598729227761,0.0,-0.0598729227761,-0.0598729227761
82,0.0598729227761,0.0,-0.0598729227761,-0.0598729227761
83,0.0598729227761,0.0,-0.0598729227761,-0.0598729227761
84,0.0598729227761,0.0,-0.0598729227761,-0.0598729227761
85,0.0598729227761,0.0,-0.0598729227761,-0.0598729227761
86,0.0598729227761,0.0,-0.0598729227761,-0.0598729227761
87,-0.0598729227761,0.0598729227761,0.0,-0.0598729227761
88,-0.0598729227761,0.0598729227761,0.0,-0.0598729227761
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95,-0.0598729227761,0.0598729227761,0.0,-0.0598729227761
96,0.0598729227761,-0.0598729227761,0.0598729227762,-0.0598729227761
97,0.0598729227761,-0.0598729227761,0.0598729227762,-0.0598729227761
98,0.0598729227761,-0.0598729227761,0.0598729227762,-0.0598729227761
99,0.0598729227761,-0.0598729227761,0.0598729227762,-0.0598729227761
100,0.0598729227761,-0.0598729227761,0.0598729227762,-0.0598729227761
101,0.0598729227761,-0.0598729227761,0.0598729227762,-0.0598729227761
102,0.0598729227761,-0.0598729227761,0.0598729227762,-0.0598729227761
103,0.0598729227761,-0.0598729227761,0.0598729227762,-0.0598729227761
104,0.0598729227761,-0.0598729227761,0.0598729227762,-0.0598729227761

plt.plot((acc.time)/100.00,acc.a1,label='A1')

数据是使用

acc = mlab.csv2rec('filename.csv')

然后像这样策划

time,a1,a2,a3,a4,a5
0,0.0598729227761,0.0598729227761,0.0,-0.0598729227761
1,0.0598729227761,0.0598729227761,0.0,-0.0598729227761
2,0.0,-0.0598729227761,0.0,-0.0598729227761
3,0.0,-0.0598729227761,0.0,-0.0598729227761
4,0.0,-0.0598729227761,0.0,-0.0598729227761
5,0.0,-0.0598729227761,0.0,-0.0598729227761
6,0.0,-0.0598729227761,0.0,-0.0598729227761
7,0.0,-0.0598729227761,0.0,-0.0598729227761
8,0.0,-0.0598729227761,0.0,-0.0598729227761
9,0.0,-0.0598729227761,0.0,-0.0598729227761
10,0.0,-0.0598729227761,0.0,-0.0598729227761
11,0.0,-0.0598729227761,0.0,-0.0598729227761
12,0.0,0.179618768328,-0.0598729227761,-0.0598729227761
13,0.0,0.179618768328,-0.0598729227761,-0.0598729227761
14,0.0,0.179618768328,-0.0598729227761,-0.0598729227761
15,0.0,0.179618768328,-0.0598729227761,-0.0598729227761
16,0.0,0.179618768328,-0.0598729227761,-0.0598729227761
17,0.0,0.179618768328,-0.0598729227761,-0.0598729227761
18,0.0,0.179618768328,-0.0598729227761,-0.0598729227761
19,0.0,0.179618768328,-0.0598729227761,-0.0598729227761
20,0.0,0.179618768328,-0.0598729227761,-0.0598729227761
21,-0.119745845552,0.0,-0.0598729227761,-0.0598729227761
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96,0.0598729227761,-0.0598729227761,0.0598729227762,-0.0598729227761
97,0.0598729227761,-0.0598729227761,0.0598729227762,-0.0598729227761
98,0.0598729227761,-0.0598729227761,0.0598729227762,-0.0598729227761
99,0.0598729227761,-0.0598729227761,0.0598729227762,-0.0598729227761
100,0.0598729227761,-0.0598729227761,0.0598729227762,-0.0598729227761
101,0.0598729227761,-0.0598729227761,0.0598729227762,-0.0598729227761
102,0.0598729227761,-0.0598729227761,0.0598729227762,-0.0598729227761
103,0.0598729227761,-0.0598729227761,0.0598729227762,-0.0598729227761
104,0.0598729227761,-0.0598729227761,0.0598729227762,-0.0598729227761

plt.plot((acc.time)/100.00,acc.a1,label='A1')

---

我希望只取唯一的值，然后绘制它。仅当行与当前行不同时才可以导入该行。然后使用数据进行绘图。

有python

set

类型，其中每个值只能有一个副本；如果您不关心行号，只需将其从行中删除，并将行馈送到集合中即可

如果需要行号，可以采用另一种方法：从行中的值生成一个元组，并使用该元组作为字典中的键，使用行号作为值