如何根据MongoDB中where条件下引用的文档详细信息获取父文档详细信息？

我有两份文件如下

const ClaimDetailsSchema = mongoose.Schema({
    _id: mongoose.Schema.Types.ObjectId,
    benefitArea: String,
    gfo: String,
    productForm: String,
    type: String,
    status: String,
    claimTitle: String,
    claimId: String,
    claimName: String,
    exception: String,
    createdBy: String,
    createdByNtId: String,
    lastModifiedBy: String,
    claimType: {
        historyId: String,
        commentId: String,
        exportId: String,
        version: String,
        reason: String
    },
    Substantiations: [{ type: mongoose.Schema.Types.ObjectId, ref: 'Substantiations' }],
    Formulaes: [{ type: mongoose.Schema.Types.ObjectId, ref: 'Formulaes' }],
    regions: [String],
    favorites: [String],
    claimCreatedDate: { type: Date, default: Date.now },
    lastModifiedDate: { type: Date }
});

module.exports = mongoose.model('ClaimDetails', ClaimDetailsSchema);

const mongoose = require('mongoose'), Schema = mongoose.Schema;

const SubstantiationSchema = mongoose.Schema({
    _id: mongoose.Schema.Types.ObjectId,
    substantiation: String
});

module.exports = mongoose.model('Substantiations', SubstantiationSchema);

我需要根据where子句中的证实文本获取索赔详情

我试过下面的方法，但没有成功

exports.testCase = (req, res) => {
    Claimdetails.find().populate({ path: 'Substantiations', match: { substantiation: 'rel' } }).exec(function (err, claims) {
        res.send({ data: claims });
    });
};

---

如果不将

匹配

条件放在填充中，它是否有效。。。它是否获取填充的数据？是的。这很吸引人。但我需要基于证实细节的ClaimDetails文档。您可以发布这两个文档的样本收集吗？LaimDetails--------------------{“\u id:“5b45af28216c031f7009999a”，“证实”：[“5B4496F53131CB44A0CD9EAAA”，“5b449702331cb44a0cd9eaab”，“公式”：[“5B4496BB331CB44A0CD9EA8”，“5B4496DE331CB44A0CD9EA9”，“区域”：[“AP”，“NA”]，“favorites:[“manjesh.m”，“rdevarap”]，“benefitArea:“保湿”，“gfo:“美容”，“产品形式”：“胶囊，硬”，“claimTitle:“带有NodeJS的测试项目”，“claimId:“CLM201800014”，“u v:”0}防晒--------------------{“id:“5B4496F5313CB44A0CD9EAAA”，“证实”：“添加测试数据”，“uu v:”0}对于您发布的数据，

证实

与

匹配：{证实：添加的测试数据}

适用于我