Mule dataweave从json数组中提取元素

Mule dataweave从json数组中提取元素,mule,dataweave,Mule,Dataweave,我有下面的json,我试图提取phones数组的某些元素。我不总是得到2个元素,它可以是1,2,或3 { "phones": [{ "id": 123, "phoneType": "H", "phoneNumber": "2125551212", "countryCode": "1", "isCellPhone": false, "optInTexting": false }, {

我有下面的json,我试图提取phones数组的某些元素。我不总是得到2个元素,它可以是1,2,或3

{
"phones": [{
        "id": 123,
        "phoneType": "H",
        "phoneNumber": "2125551212",
        "countryCode": "1",
        "isCellPhone": false,
        "optInTexting": false
    }, {
        "id": 456,
        "phoneType": "W",
        "phoneNumber": "9197776262",
        "countryCode": "1",
        "isCellPhone": true,
        "optInTexting": true
    }
]
}

这就是我对输出的看法:

%output application/java
---
{
   HOMEPH:  payload.phones filter ($.phoneType == "H") map {HOMEPH:.phoneNumber},
   WORKPH:  payload.phones filter ($.phoneType == "W") map {WORKPH:$.phoneNumber}
}
我从中得到的结果是:

HOMEPH: [{HOMEPH=2125551212}]
WORKPH: [{WORKPH=9197776262}]
我想要的是:

HOMEPH: "2125551212",
WORKPH: "9197776262"

由于您将输出用作
application/java
,因此可以尝试以下操作:

%dw 1.0
%output application/java
---
{
    (payload.phones filter ($.phoneType == "H") map {HOMEPH:$.phoneNumber}),
    (payload.phones filter ($.phoneType == "W") map {WORKPH:$.phoneNumber})
}
您将获得如下输出:

如果在Dataweave之后将对象添加到字符串转换器,您将获得:

{HOMEPH=2125551212, WORKPH=9197776262}

由于您将输出用作
application/java
,因此可以尝试以下操作:

%dw 1.0
%output application/java
---
{
    (payload.phones filter ($.phoneType == "H") map {HOMEPH:$.phoneNumber}),
    (payload.phones filter ($.phoneType == "W") map {WORKPH:$.phoneNumber})
}
您将获得如下输出:

如果在Dataweave之后将对象添加到字符串转换器,您将获得:

{HOMEPH=2125551212, WORKPH=9197776262}
试试下面的方法

%output application/java
---
{
   HOMEPH:  (payload.phones filter ($.phoneType == "H") map ($.phoneNumber)) [0],
   WORKPH:  (payload.phones filter ($.phoneType == "W") map ($.phoneNumber)) [0]
}

第二个选项更有效,因为它只迭代一次有效负载。 希望这有帮助。

尝试以下方法

%output application/java
---
{
   HOMEPH:  (payload.phones filter ($.phoneType == "H") map ($.phoneNumber)) [0],
   WORKPH:  (payload.phones filter ($.phoneType == "W") map ($.phoneNumber)) [0]
}

第二个选项更有效,因为它只迭代一次有效负载。
希望这能有所帮助。

是的,这正是我想要的。因为我过滤到数组中的一个元素,并且我想要这个元素[0],所以它提取我所需要的。非常感谢。是的,这就是我要找的。因为我过滤到数组中的一个元素,并且我想要这个元素[0],所以它提取我所需要的。非常感谢。