Mysql 查询SQL列两次以构建HTML表

所以我有两个SQL表。一张表（我们称之为团队）如下所示：

team_id | team_name 
--------|-----------
    0   |    team_A
    1   |    team_B

game_id | home_team_id | away_team_id | date 
--------|--------------|--------------|-----------
    0   |       0      |        1     | 2013-11-05
    1   |       1      |        0     | 2013-11-07

另一个表（称为schedule）如下所示：

team_id | team_name 
--------|-----------
    0   |    team_A
    1   |    team_B

game_id | home_team_id | away_team_id | date 
--------|--------------|--------------|-----------
    0   |       0      |        1     | 2013-11-05
    1   |       1      |        0     | 2013-11-07

如何构造SQL查询以创建如下所示的表

home_team | away_team | date
----------|-----------|-----------
  Team_A  |  Team_B   | 2013-11-05
  Team_B  |  Team_A   | 2013-11-07

我试过使用

SELECT schedule.date, teams.team_name AS home_team, 
       teams.team_name AS away_team 
FROM schedule 
   INNER JOIN teams ON schedule.home_team_id = teams.team_id 
   INNER JOIN schedule team ON schedule.away_team_id = teams.team_id

---

但这不会返回任何结果。

您需要加入两次团队，使用别名来区分：

SELECT schedule.date, ht.team_name AS home_team, 
       at.team_name AS away_team 
FROM schedule 
   INNER JOIN teams ht ON schedule.home_team_id = ht.team_id 
   INNER JOIN teams at ON schedule.away_team_id = at.team_id;

试试下面的方法-

SELECT t1.team_name AS home_team, 
             t2.team_name AS away_team,
            schedule.date
FROM schedule
   INNER JOIN teams t1 ON schedule.home_team_id = t1.team_id 
   INNER JOIN teams t2 ON schedule.away_team_id = t2.team_id
order by schedule.date

执行上述操作时，u将得到

team_A  team_B  2013-11-05
team_B  team_A  2013-11-07