两个mysql表列的总和

两个mysql表列的总和,mysql,join,sum,Mysql,Join,Sum,我有两个mysql表: table: loan -------------------------------------------------------- id | advance_id | loan_amount | deposit_amount | date -------------------------------------------------------- 1 | 22556678 | 5000 | 0 | 2015-02-06 2 | 22556678 | 500

我有两个mysql表:

table: loan
--------------------------------------------------------
 id | advance_id | loan_amount | deposit_amount | date
--------------------------------------------------------
 1 | 22556678 | 5000 | 0 | 2015-02-06
 2 | 22556678 | 5000 | 0 | 2015-02-07
--------------------------------------------------------

table: advance
--------------------------------------------------------
id | advance_id | advance_amount | purpose | date
--------------------------------------------------------
 1 | 22556678 | 20000 | purchase | 2015-01-30
 2 | 22556678 | 10000 | purchase | 2015-01-31
我想从表:loan中获取“loan\u amount”的和,从表:advance中获取“advance\u amount”的和,在一个由内部联接连接的mysql查询中

如何从两个表的列中求和

SELECT 
  a.advance_id,
  SUM(a.advance_amount) AS adv_amount,
  a.purpose,
  a.date,
  SUM(l.loan_amount) AS loan_amount 
FROM
  advance AS a 
  INNER JOIN loan AS l 
    ON a.advance_id = l.advance_id 
GROUP BY a.advance_id 
HAVING SUM(l.loan_amount) - SUM(l.deposit_amount) > 0 

您可以将查询重写为

SELECT 
  a.advance_id,
  SUM(a.advance_amount) AS adv_amount,
  a.purpose,
  a.date,
  l.loan_amount 
FROM
  advance AS a 
  INNER JOIN 
  (
    SELECT advance_id,SUM(deposit_amount) AS loan_amount
    FROM loan
    GROUP BY advance_id
    HAVING SUM(loan_amount) - SUM(deposit_amount) > 0 
  )  AS l USING(advance_id)
GROUP BY a.advance_id 

选择a.advance\u id,sum(a.advance\u amount)作为adv\u amount,a.purpose,a.date,sum(l.loan\u amount),sum(l.loan\u amount),sum(l.loan\u amount),sum(l.loan\u amount),sum(l.loan\u amount)作为内部联接贷款作为l ON a.advance\u id=l.advance\u id组,由a.advance\u id组成,sum(a.advance\u amount