将语法与联接一起使用时从MYSQL查询中排除

我有疑问

SELECT table1.name, table2.wage, table3.bonus table5.shift
FROM table1
    INNER JOIN table2 ON table1.userid = table2.userid
    INNER JOIN table3 ON table2.userid = table3.userid
    LEFT JOIN table5 ON table1.userid = table5.userid;

我还需要查看表“假期”，并将它们从上述查询中排除

"vacation.userid" = "table1.userid"

像

---

但由于某些原因，这仍然会在列表中显示它们。

尝试将休假表作为左联接包含在列表中，然后添加WHERE子句以获取休假联接失败的记录

SELECT table1.name, table2.wage, table2.bonus table3.shift, table4.vacation
   FROM table1
INNER JOIN table2 ON table1.userid = table2.userid
INNER JOIN table3 ON table2.userid = table3.userid
INNER JOIN table4 ON table4.userid = table4.userid 
LEFT JOIN table5 ON table1.name = table5.position
LEFT JOIN vacation on vacation.userid = table1.userid
WHERE vacation.userid IS NULL;

---

请注意，只有在假期中userid是唯一的时，这才起作用。如果人们可以有多个假期记录，您将在查询中得到重复的记录。请参阅我发布的

NOT EXISTS

版本以获取替代方案。我有点困惑--这有助于回答问题，但您仍然需要一种不同的方法来解决问题？这是家庭作业还是什么？

SELECT table1.name, table2.wage, table2.bonus table3.shift, table4.vacation
   FROM table1
INNER JOIN table2 ON table1.userid = table2.userid
INNER JOIN table3 ON table2.userid = table3.userid
INNER JOIN table4 ON table4.userid = table4.userid 
LEFT JOIN table5 ON table1.name = table5.position
LEFT JOIN vacation on vacation.userid = table1.userid
WHERE vacation.userid IS NULL;

SELECT table1.name, table2.wage, table2.bonus table3.shift
FROM table1
    INNER JOIN table2 ON table1.userid = table2.userid
    INNER JOIN table3 ON table2.userid = table3.userid
    LEFT JOIN table5 ON table1.name = table5.position
    LEFT JOIN vacation ON vacation.userid = table1.userid
WHERE
    vacation.userid IS NULL;

SELECT table1.name, table2.wage, table3.bonus table5.shift
FROM table1
    INNER JOIN table2 ON table1.userid = table2.userid
    INNER JOIN table3 ON table2.userid = table3.userid
    LEFT JOIN table5 ON table1.userid = table5.userid;
WHERE NOT EXISTS
    (SELECT * FROM vacation WHERE vacation.userid = table1.userid)