如何在MySQL中进行不同的排序？

我有这个：

从TA中选择put\U id、ut\U id、cm\U tx、da、un

ut_id  | put_id  |        cm_tx             | da         |   un
 ------|---------|--------------------------|------------|--------
 21    | 21      |  was good                | 1523190974 |  Jonah
 22    | 21      |  thx                     | 1523197793 |  Sara
 23    | 23      |  that was good post      | 1523201196 |  Tom
 24    | 24      |  not good                | 1523208390 |  Lucas
 25    | 24      |  not good??              | 1523718726 |  Stephen
 26    | 24      |  why u said not good?    | 1523718805 |  Stephen
 27    | 24      |  tell me why u said?     | 1523718886 |  Stephen

我想要的是：

ut_id  | put_id  |        cm_tx             | da         |   un
 ------|---------|--------------------------|------------|--------
 21    | 21      |  was good                | 1523190974 |  Jonah
 22    | 21      |  thx                     | 1523197793 |  Sara
 23    | 23      |  that was good post      | 1523201196 |  Tom
 24    | 24      |  not good                | 1523208390 |  Lucas
 27    | 24      |  tell me why u said?     | 1523718886 |  Stephen
 26    | 24      |  why u said not good?    | 1523718805 |  Stephen
 25    | 24      |  not good??              | 1523718726 |  Stephen

（事实上，我想按da和put_id对唯一的“ut_id！=put_id”）订单进行排序

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提前感谢

我从您想要的输出中了解到，您希望按put\u id排序，然后按ut\u id=put\u id，然后按日期降序排序。您可以通过以下方式实现这一点：

SELECT put_id,ut_id,cm_tx,date,un FROM TA ORDER BY put_id ASC, IF(ut_id = put_id, 0, 1) ASC, date DESC 

输出：

put_id ut_id   cm_tx                 date           un  
21     21      was good              1523190974     Jonah
21     22      thx                   1523197793     Sara
23     23      that was good post    1523201196     Tom
24     24      not good              1523208390     Lucas
24     27      tell me why u said?   1523718886     Stephen
24     26      why u said not good?  1523718805     Stephen
24     25      not good??            1523718726     Stephen

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您是否尝试过按put_id asc、put_id descyes下单，但这不起作用这是此订单的逻辑依据？？？我想要排序ut_id！=顺序背后的逻辑不清楚，至少对我来说不清楚<代码>按ut_id订购！=put_id没有任何意义。谢谢，你准确地解决了问题