Mysql sql从2表中选择并计数

第一表（公司）

第二张表（操作）

结果应该是这样的

LOGO         Total      new     repaired    Consists    
../763.jpg     4         2          1          1
../345.jpg     2         2          0          0
../678.jpg     3         0          2          1

---

使用

联接

和条件聚合：

select c.logo, count(*) as total,
       sum( status = 'new' ) as new,
       sum( status = 'repaired' ) as repaired,
       sum( status = 'consists' ) as consists,
from company c left join
     operations o
     on c.id = o.company_id
group by c.logo;

---

您也可以使用下面的查询

select 
c.logo, 
(select count(1) from operation where company_id = o.company_id group by company_id) 
as Total,
(select count(1) from operation where company_id = o.company_id and status = 'new' 
group by status) as new,
(select count(1) from operation where company_id = o.company_id and status = 
'repaired' group by status) as repaired,
(select count(1) from operation where company_id = o.company_id and status = 
'consists' group by status) as consists
from
company c
inner join operation o
on (c.id = o.company_id);

---

@戈登，很好的提问方式。向你学习更多

select c.logo, count(*) as total,
       sum( status = 'new' ) as new,
       sum( status = 'repaired' ) as repaired,
       sum( status = 'consists' ) as consists,
from company c left join
     operations o
     on c.id = o.company_id
group by c.logo;

select 
c.logo, 
(select count(1) from operation where company_id = o.company_id group by company_id) 
as Total,
(select count(1) from operation where company_id = o.company_id and status = 'new' 
group by status) as new,
(select count(1) from operation where company_id = o.company_id and status = 
'repaired' group by status) as repaired,
(select count(1) from operation where company_id = o.company_id and status = 
'consists' group by status) as consists
from
company c
inner join operation o
on (c.id = o.company_id);