Mysql 需要按起始年和其后每年分组的事实行的总和

我有两张桌子：

• customers

  表，带有列

  customer\u id

  ，

  已在

• 订单

  表，带列

  订单id

  ，

  客户id

  ，

  付款地点

  ，

  金额

我必须编写一个SQL查询，根据客户注册的年份（他们的队列年）对客户进行细分，并确定这些年中每个队列的总年收入（例如，2011年队列第一年的总收入为x美元，第二年的总收入为y美元，等等）

按年份分组（日期列）

---

由于这是一个客户细分，因此

客户id

在最终输出中没有意义，只有队列年是重要的

select YEAR(c.created_at), SUM(o.amount) as Tot_amt
from customers c inner join orders o using(customer_id)
group by YEAR(c.created_at);

---

支持你的说法

2011年第1年的总收入为x美元，第2年为y美元

您的订单表中应该有orderDate

select 
  YEAR(c.created_at) as cohortYear, 
(YEAR(orderDate)-YEAR(c.created_at)+1) as YearNum,
SUM(o.amount) OVER( PARTITION by YEAR(c.created_at),(YEAR(orderDate)-YEAR(c.created_at)) ORDER BY YEAR(c.created_at),(YEAR(orderDate)-YEAR(c.created_at))) as Tot_amt
from customers c inner join orders o on c.customer_id = o.customer_id

如果您需要使用group by的解决方案

select 
  YEAR(c.created_at) as cohortYear, 
(YEAR(orderDate)-YEAR(c.created_at)+1) as YearNum,
SUM(o.amount) as Tot_amt
from customers c inner join orders o on c.customer_id = o.customer_id
group by YEAR(c.created_at),(YEAR(orderDate)-YEAR(c.created_at)+1)
order by YEAR(c.created_at),(YEAR(orderDate)-YEAR(c.created_at))

select 
  YEAR(c.created_at) as cohortYear, 
(YEAR(orderDate)-YEAR(c.created_at)+1) as YearNum,
SUM(o.amount) OVER( PARTITION by YEAR(c.created_at),(YEAR(orderDate)-YEAR(c.created_at)) ORDER BY YEAR(c.created_at),(YEAR(orderDate)-YEAR(c.created_at))) as Tot_amt
from customers c inner join orders o on c.customer_id = o.customer_id

select 
  YEAR(c.created_at) as cohortYear, 
(YEAR(orderDate)-YEAR(c.created_at)+1) as YearNum,
SUM(o.amount) as Tot_amt
from customers c inner join orders o on c.customer_id = o.customer_id
group by YEAR(c.created_at),(YEAR(orderDate)-YEAR(c.created_at)+1)
order by YEAR(c.created_at),(YEAR(orderDate)-YEAR(c.created_at))