同一表上的MySQL计数子查询
我有一个疑问:同一表上的MySQL计数子查询,mysql,sql,database,Mysql,Sql,Database,我有一个疑问: SELECT `facilities`.`name` AS facility, `countries`.`name` AS country, `states`.`name` AS state, `users`.`dosage` AS dosage, COUNT(`users`.`id`) AS registrations FROM `users` LEFT JOIN `countries` ON `users`.`country_id` = `countries`.`id`
SELECT `facilities`.`name` AS facility, `countries`.`name` AS country, `states`.`name` AS state, `users`.`dosage` AS dosage, COUNT(`users`.`id`) AS registrations
FROM `users`
LEFT JOIN `countries` ON `users`.`country_id` = `countries`.`id`
LEFT JOIN `states` ON `users`.`state_id` = `states`.`id` LEFT JOIN `user_facilities` ON `users`.`id` = `user_facilities`.`user_id`
LEFT JOIN `facilities` ON `user_facilities`.`facility_id` = `facilities`.`id`
WHERE `users`.`dosage` != "Not sure"
GROUP BY `facilities`.`name`, `countries`.`name`, `states`.`name`, `users`.`dosage`
ORDER BY `facilities`.`id` ASC, `countries`.`id` ASC, `states`.`name` ASC
它给了我这个结果:
Hospital | United States | Arkansas | 10 doses | 3
Hospital | United States | Arkansas | >10 doses | 4
Home care | United States | Arkansas | 10 doses | 1
Home care | United States | Texas | 10 doses | 1
我的用户表:
id |电子邮件|州id |国家id |剂量|完成百分比|
我需要做的是为每个结果获取完成百分比=100的用户数。我尝试了子查询,但找不到适合此项的子查询。我卡住了。有人有什么建议吗?
谢谢。如果我理解正确,您可以使用条件聚合。在MySQL中,您只需执行以下操作:
select . . .,
sum(percent_completed = 100) as num_at_100
如果我理解正确,您可以使用条件聚合。在MySQL中,您只需执行以下操作:
select . . .,
sum(percent_completed = 100) as num_at_100
在分组后,请添加“已完成总数(完成百分比)>=100”,这将使您的用户计数已完成>=100%的用户
SELECT `facilities`.`name` AS facility, `countries`.`name` AS country, `states`.`name` AS state, `users`.`dosage` AS dosage, COUNT(`users`.`id`) AS registrations
FROM `users`
LEFT JOIN `countries` ON `users`.`country_id` = `countries`.`id`
LEFT JOIN `states` ON `users`.`state_id` = `states`.`id` LEFT JOIN `user_facilities` ON `users`.`id` = `user_facilities`.`user_id`
LEFT JOIN `facilities` ON `user_facilities`.`facility_id` = `facilities`.`id`
WHERE `users`.`dosage` != "Not sure"
GROUP BY `facilities`.`name`, `countries`.`name`, `states`.`name`, `users`.`dosage` having sum(users.percentage_completed) >= 100
ORDER BY `facilities`.`id` ASC, `countries`.`id` ASC, `states`.`name` ASC
在分组后,请添加“已完成总数(完成百分比)>=100”,这将使您的用户计数已完成>=100%的用户
SELECT `facilities`.`name` AS facility, `countries`.`name` AS country, `states`.`name` AS state, `users`.`dosage` AS dosage, COUNT(`users`.`id`) AS registrations
FROM `users`
LEFT JOIN `countries` ON `users`.`country_id` = `countries`.`id`
LEFT JOIN `states` ON `users`.`state_id` = `states`.`id` LEFT JOIN `user_facilities` ON `users`.`id` = `user_facilities`.`user_id`
LEFT JOIN `facilities` ON `user_facilities`.`facility_id` = `facilities`.`id`
WHERE `users`.`dosage` != "Not sure"
GROUP BY `facilities`.`name`, `countries`.`name`, `states`.`name`, `users`.`dosage` having sum(users.percentage_completed) >= 100
ORDER BY `facilities`.`id` ASC, `countries`.`id` ASC, `states`.`name` ASC
你能给我们结构和一些样本数据作为sql语句吗?你能给我们结构和一些样本数据作为sql语句吗?非常感谢,这正是我需要的:)非常感谢,这正是我需要的:)谢谢你的回答。“Having”删除完成百分比为0的数据。条件聚合解决了我的问题:)谢谢你的回答。“Having”删除完成百分比为0的数据。条件聚合解决了我的问题:)