在MySQL中，如何限制查询结果占结果总数的百分比？

下面的mysql问题只返回前10行。我怎样才能将它们限制在总数的10%以内

SELECT page, 
       poso, 
       diff 
FROM   (SELECT page, 
               Count(*) AS poso, 
               ( Sum(Date(timestamp) = Curdate()) - Sum( 
                 Date(timestamp) = Date_sub(Curdate(), 
                                   INTERVAL 1 day)) ) 
                        diff 
        FROM   `behaviour` 
        WHERE  Date(timestamp) >= Date_sub(Curdate(), INTERVAL 1 day) 
        GROUP  BY page 
        ORDER  BY ( Sum(Date(timestamp) = Curdate()) - Sum( 
                    Date(timestamp) = Date_sub(Curdate(), 
                               INTERVAL 1 day)) 
                  ) DESC 
        LIMIT  10) AS u 
ORDER  BY diff DESC 

改编自：

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此处演示：

可能重复谢谢！我已经接受了你的答案，我会在14小时内给你奖励

SELECT page,
       poso,
       diff
FROM    (
    SELECT *,
           @counter := @counter + 1 AS counter
    FROM   (select @counter:=0) AS initvar, 
           (SELECT page, 
                   Count(*) AS poso, 
                   ( Sum(Date(timestamp) = Curdate()) - Sum( 
                     Date(timestamp) = Date_sub(Curdate(), 
                                       INTERVAL 1 day)) ) 
                            diff
            FROM   `behaviour` 
            WHERE  Date(timestamp) >= Date_sub(Curdate(), INTERVAL 1 day) 
            GROUP  BY page 
            ORDER  BY ( Sum(Date(timestamp) = Curdate()) - Sum( 
                        Date(timestamp) = Date_sub(Curdate(), 
                                   INTERVAL 1 day)) 
                      ) DESC) AS u
) AS v
WHERE counter <= 10/100 * @counter
ORDER  BY diff DESC;