Mysql 选择id列表并更新这些行

我有以下MySQL语句：

UPDATE xxx_iop_user_plans
SET state = 1, accepted = 1
WHERE id IN (SELECT iup1.id FROM xxx_iop_user_plans iup1
INNER JOIN xxx_iop_user_ed iue ON iup1.user_id = iue.user_id
WHERE iue.parent_id = 44 AND iup1.iop_id = 11)

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我应该如何更新此语句以更新从SELECT语句返回的列表中存在id号的行？

我希望您的update语句能够做到这一点。如果它没有更新所有这些ID，它在做什么？您可以重新组织查询，将select子查询放入from子句中：

UPDATE x 
SET state = 1, accepted = 1
FROM xxx_iop_user_plans x 
    INNER JOIN (
        SELECT iup1.id 
        FROM xxx_iop_user_plans iup1
            INNER JOIN xxx_iop_user_ed iue ON iup1.user_id = iue.user_id
        WHERE iue.parent_id = 44 AND iup1.iop_id = 11
    ) y ON x.ID = y.ID

但我不希望这与你已经拥有的有任何不同。还是试试看。

您应该使用MySQL，如下所示：

UPDATE xxx_iop_user_plans
  INNER JOIN xxx_iop_user_ed ON xxx_iop_user_plans.user_id = xxx_iop_user_ed.user_id
SET state = 1, accepted = 1
WHERE xxx_iop_user_ed.parent_id = 44 
  AND xxx_iop_user_plans.iop_id = 11;

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您的意思是‘更新select语句返回的列表中具有id列值的每一行’？或者您正在尝试更改id列的值？